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Difficulty:
45%
(medium)
Question Stats:
69% (02:11) correct
31%
(02:38)
wrong
based on 248
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Pipe A can fill a tank in 90 minutes. Pipe B whose diameter is 3 times that of Pipe A also fills the tank. lf both the pipes are kept open when the tank is empty, how long will the pipes take to fill the tank
A) 7 minutes
B) 9 minutes
C) 5 minutes
D) 6 minutes
E) 10 minutes
A) 7 minutes
B) 9 minutes
C) 5 minutes
D) 6 minutes
E) 10 minutes
03 May 2020, 20:52
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anuspn
Pipe A = 90 Minutes
Pipe B = 3 times diameter of A = 3^2 times volume of A = (1/9) time of A = (1/9)*90 = 10 minutes
Volume \(= πr^2h\)
Let, Tank capacity = 90 Liters
Volume input by tank A in 1 minute = 90/90 = 1 liter
Volume input by tank B in 1 minute = 90/10 = 9 liter
Volume input by tank A and B both in 1 minute = 1+9 = 10 liter
Time for both = 90/10 = 9 minutes
Answer: Option B
General Discussion
03 May 2020, 11:52
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The rate of pipe B will be directly proportional to square of radius of pipe A. Assume the pipes to be cylinders with equal lengths ( height in the formula ), then
volume of that cylinder = π r^2 h
so the time taken will be inversely proportional to square of radius.
time taken by pipe B = 90/ 3^2 = 10min
Now we can easily find time taken when both are open simultaneously.
Posted from my mobile device
volume of that cylinder = π r^2 h
so the time taken will be inversely proportional to square of radius.
time taken by pipe B = 90/ 3^2 = 10min
Now we can easily find time taken when both are open simultaneously.
Posted from my mobile device
