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Bunuel
Which of the following does NOT have a remainder of 7 when divided by 9 ?

A. 61
B. 88
C. 106
D. 115
E. 134


PS21173

Divisibility test of 9 : Sum of the digits must be divisible by 9

A. 61 Digit sum = 7 i.e. 2 short of 9 or 7 excess i.e. remainder = 7
B. 88 Digit sum = 16 = 7 i.e. 2 short of 9 or 7 excess i.e. remainder = 7
C. 106 Digit sum = 7 i.e. 2 short of 9 or 7 excess i.e. remainder = 7
D. 115 Digit sum = 7 i.e. 2 short of 9 or 7 excess i.e. remainder = 7
E. 134 Digit sum = 8 i.e. 1 short of 9 or 8 excess i.e. remainder = 8

Answer: Option E
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Bunuel
Which of the following does NOT have a remainder of 7 when divided by 9 ?

A. 61
B. 88
C. 106
D. 115
E. 134


PS21173


A. 61 = 9*6 + 7
B. 88 = 9*9 + 7
C. 106 = 9*11 + 7
D. 115 = 9*12 + 7
E. 134 = 9*12 + 8 , Answer must be (E)
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Bunuel
Which of the following does NOT have a remainder of 7 when divided by 9 ?

A. 61
B. 88
C. 106
D. 115
E. 134



Solution:

134/9 = 14 remainder 8

Alternate Solution:

Let’s subtract 7 from each answer choice. The amended answer choice that is not evenly divisible by 9 is the correct answer.

The amended answer choices are 54, 81, 99, 108, and 127. All of these are evenly divisible by 9 except 127; thus, choice E (127 + 7 = 134) is the correct answer.


Answer: E
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