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Minimum Gross Profit is When the Cost Price is maximum and selling price is minimum.
The maximum cost price at which he can purchase a book = $1.5/book

The minimum selling price at which he can sell book is = $3/book

S.P. - C.P. = Profit
20(3)-20(1.5)
60-30
30$..
Answer is B

Posted from my mobile device
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Bunuel
A book dealer buys used books for prices ranging from $0.75 to $1.50 and then sells them for prices ranging from $3.00 to $5.50. If the dealer were to sell 20 of these books, the minimum gross profit from this sale would be

A. $15
B. $30
C. $45
D. $50
E. $80


PS21158
\(GP_{Min} = SP_{Min} - CP_{Max}\)

Or, \(GP_{Min} = 20 ( 3.00 - 1.50 )\)

Or, \(GP_{Min} = 30\), Answer must be (B)
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Minimum profit when bought at the highest possible price and sold at a minimum price.

Minimum profit when all 20 books were bought at $1.50 and sold at $3.00 i.e. profit on each book will be $1.50 ($3.00 - $1.50).

Profit = 20 * 1.50 = $30.

B.
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Bunuel
A book dealer buys used books for prices ranging from $0.75 to $1.50 and then sells them for prices ranging from $3.00 to $5.50. If the dealer were to sell 20 of these books, the minimum gross profit from this sale would be

A. $15
B. $30
C. $45
D. $50
E. $80



The minimum profit for each book occurs when he sells the $1.50 (cost) books for $3.00 each, making $1.50 on each book. Thus, the minimum gross profit for selling 20 such books is 20 x $1.50 = $30.

Answer: B
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Bunuel
A book dealer buys used books for prices ranging from $0.75 to $1.50 and then sells them for prices ranging from $3.00 to $5.50. If the dealer were to sell 20 of these books, the minimum gross profit from this sale would be

A. $15
B. $30
C. $45
D. $50
E. $80


PS21158

Everyone is trying the typical method . Lately I discovered this new approach as I always get confused in min max calc I have turned these questions into min distance and max distance on NUMBER LINE .

we know profit = S.P - C.P so lets draw these values on number line
.75(CP)____1.50 (CP)___________3(sp)_________5.50(sp) Now to ensure minimum profit we can try minimise the distance between CP and SP . In other words we want to maximise the CP and minimize the SP .
Hence 20 (1.50 -3) = 30$
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­Optimize for the lowest profit per book (highest cost and lowest sell price), and multiply by 20:

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