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15 Jun 2020, 00:17
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
82% (01:55) correct
18%
(02:19)
wrong
based on 149
sessions
History
Date
Time
Result
Not Attempted Yet
If 500 pounds of mush will feed 20 pigs for one week, for how many days will 200 pounds of mush feed 14 pigs?
A. 4
B. 5
C. 6
D. 7
E. 8
A. 4
B. 5
C. 6
D. 7
E. 8
15 Jun 2020, 00:22
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Bunuel
CONCEPT: \(\frac{(Machine_Power * Time)}{Work} = Constant\)
i.e. \(\frac{(M_1 * T_1)}{W_1} = \frac{(M_2 * T_2)}{W_2}\)
i.e. \(\frac{(M_1 * T_1)}{W_1} = \frac{(M_2 * T_2)}{W_2}\)
i.e. \(\frac{(20 * 7)}{500} = \frac{(14 * T_2)}{200}\)
i.e. \(T_2 = 4\)
Answer: Option A
15 Jun 2020, 00:32
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(days*time*manpower)/work = constant
(7 days*20 pigs)/500 pounds = (x days*14 pigs)/200 pounds
cancel the like terms
x=4 days
(7 days*20 pigs)/500 pounds = (x days*14 pigs)/200 pounds
cancel the like terms
x=4 days
