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Explanation:

Given: x + 3 is a multiple of 3
so, x is also multiple of 3.
x can be 3,6,9..... etc.

So , by checking option. Only C is not divisible by 3

IMO-C
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IMO C

X+3 to be a multiple of 3 , X must be a multiple of 3. As the remeainder is 0 when the constant 3 (in X+3) is divided by 3.

Since any integer multiplied by a multiple of 3 , the result will also be a multiple of 3.

So we just need to check wether the constants in the Answer choices are multiples of 3.

In C. 5 is not a multiple of 3. Hence answer is 3X+5

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X is positive and X+3 is multiple of 3
X = 3,6,9,12,15,18,21,24,27,30,33,36,39,42.............................................

only option C is not adding multiple of 3 in X
ANS : C
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SajjadAhmad
If x > 0, and if x + 3 is a multiple of 3, which of the following is not a multiple of 3?

(A) x

(B) x + 6

(C) 3x + 5

(D) 2x + 6

(E) 6x + 18

given x>0 and x+3 is multiple of 3
least x has to be is 3
now test with options
(A) x ; yes

(B) x + 6 ; yes

(C) 3x + 5 ; NO

(D) 2x + 6 ; yes

(E) 6x + 18; yes
OPTION C ; is not multiple of C
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It is evident that any multiple of x and x+3 will be a multiple of 3. Only option which is not is option C.

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