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03 Jul 2020, 03:46
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In the given diagram, the circle touches the y-axis at the point K whose coordinate is (0,7). If the area of triangle CKO is 21 units^2, where C is the centre of the circle, find the area of the circle.
A. 16π
B. 21π
C. 24π
D. 36π
E. 49π
Attachment:
1.png [ 15.99 KiB | Viewed 3794 times ]
03 Jul 2020, 03:57
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Explanation:
Triangle CKO will be right angle triangle.
With Base as CK (which also radius of circle), Height as KO = 7
Area of Triangle = 21
1/2 x B X H = 21
1/2 x B x 7 =21
B = 6
Radius 6
Area of circle = πr^2 = 36π
IMO-D
Triangle CKO will be right angle triangle.
With Base as CK (which also radius of circle), Height as KO = 7
Area of Triangle = 21
1/2 x B X H = 21
1/2 x B x 7 =21
B = 6
Radius 6
Area of circle = πr^2 = 36π
IMO-D
Neha2404
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03 Jul 2020, 08:23
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IMO-D
Area of triangle is =1/2*b*h
Here height is given=7
Area=21
21=1/2*7*b
B=6
Base is equal to radius of circle
Area of circle =pi r^2
=36 pi
Posted from my mobile device
Area of triangle is =1/2*b*h
Here height is given=7
Area=21
21=1/2*7*b
B=6
Base is equal to radius of circle
Area of circle =pi r^2
=36 pi
Posted from my mobile device
Thanks! 
