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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 21 Jul 2020, 04:25
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73% (02:23) correct 27% (01:59) wrong based on 244 sessions

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On New Year's Eve, a limousine driver traveled from Philadelphia to Pittsburgh at an average rate of 75 miles per hour. On his return trip to Philadelphia, he encountered a heavy snow storm, which reduced his speed to 45 miles per hour. What was the limousine driver's average speed for the entire trip, in miles per hour?

A. 55
B. 56
C. 58
D. 60
E. 62
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B
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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 21 Jul 2020, 08:53
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Bunuel
On New Year's Eve, a limousine driver traveled from Philadelphia to Pittsburgh at an average rate of 75 miles per hour. On his return trip to Philadelphia, he encountered a heavy snow storm, which reduced his speed to 45 miles per hour. What was the limousine driver's average speed for the entire trip, in miles per hour?

A. 55
B. 56
C. 58
D. 60
E. 62
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since distance is same
so avg speed = 2 *a*b/( a+b)
=> 2*45*75 /120 ; 56
OPTION B
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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 24 Jul 2020, 15:36
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Bunuel
On New Year's Eve, a limousine driver traveled from Philadelphia to Pittsburgh at an average rate of 75 miles per hour. On his return trip to Philadelphia, he encountered a heavy snow storm, which reduced his speed to 45 miles per hour. What was the limousine driver's average speed for the entire trip, in miles per hour?

A. 55
B. 56
C. 58
D. 60
E. 62
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Avg. Speed = \(\frac{2*75*45}{75+45}= 56.25 \)

So closest answer 56
Ans- B
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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 24 Jul 2020, 21:04
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Bunuel
On New Year's Eve, a limousine driver traveled from Philadelphia to Pittsburgh at an average rate of 75 miles per hour. On his return trip to Philadelphia, he encountered a heavy snow storm, which reduced his speed to 45 miles per hour. What was the limousine driver's average speed for the entire trip, in miles per hour?

A. 55
B. 56
C. 58
D. 60
E. 62
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CONCEPT: \(AVerage-Speed = \frac{Total-Distance}{Total-Time}\)

For same distance travelled forward and backward, \(AVerage-Speed = \frac{2*a*b*}{a+b}\)

a = 75 and b = 45

\(Average Speed = \frac{2*75*45}{75+45} = \frac{150*45}{120} = 56.25\)



Answer: Option B
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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 14 Aug 2020, 22:56
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How did you come up with that formula?
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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 15 Aug 2020, 06:39
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Average speed = \(\frac{2*a*b }{ a+b}\)

=> \(\frac{2*75*45}{75+45}\)

=> \(\frac{2*75*45}{120}\)

=> 56.25

Answer B
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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 10 Nov 2024, 16:54
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I'm sorry, but this seems like a bad question. The result (56.25 mph) is not represented in any answer. Answer B is the closest, but the question does not ask for closest or an estimation.
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MustafaChang
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On New Year's Eve, a limousine driver traveled from Philadelphia to Pi 12 Nov 2024, 10:03
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i dont get this. how is the total time 45+75??
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