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Bunuel
If xy < 0, which of the following must be negative ?


A. \(xy^2\)

B. \(x^2y\)

C. \(x^2y^2\)

D. \(x^2y^3\)

E. \(x^3y^3\)

xy < 0

i.e. one of x and y is negative and one of positive

Let's check Option with focus on "MUST be Negative"

A. \(xy^2\) It will be positive if x is positive and y is negative so OUT

B. \(x^2y\) It will be positive if y is positive and x is negative so OUT

C. \(x^2y^2\) It will always be positive

D. \(x^2y^3\) It will be positive if y is positive and x is negative so OUT

E. \(x^3y^3\) It will always be Negative

Answer: Option E
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If xy < 0, which of the following must be negative ?


A. xy^2

B. x^2y

C. x^2y^2

D. x^2y^3

E. x^3y^3

Explanation:

Given xy<0
Means x & y are of opposite signs

i.e either x>0,y<0 OR x<0 ,y>0

Checking each option one by one ,Only in option E
(x.y)^3<0
As here too the condition of opposite signs of x& y exists.

Hence E is the correct answer.

Regards
Atul Pandey

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Bunuel
If xy < 0, which of the following must be negative?


A. \(xy^2\)

B. \(x^2y\)

C. \(x^2y^2\)

D. \(x^2y^3\)

E. \(x^3y^3\)

According to the condition, either x or y is negative.

A. If x is negative then A is the answer, but x could be positive and y could be positive then the value will be positive. So A is out.
B. X could be negative, the result will be positive. B is out.
C. the answer will negative if only y is negative but it could positive and then the answer will be positive. So option C is out.
D. True if y is negative but false if y is negative.
E. For either sign of x and y the result the answer well be negative.

The answer is E.
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