The diameter of a circle is formed by the line joining points (5, -2)

Question

The diameter of a circle is formed by the line joining points (5, -2) and (-5, 3). Find the circumference of the circle.

A.  5\pi\sqrt{2} 
B.  5\pi\sqrt{3} 
C.  5\pi\sqrt{4} 
D.  5\pi\sqrt{5} 
E.  5\pi\sqrt{6}

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Sumi1010 · Answer

Diameter length Sqrt(((5-(-5))^2 + (-2-3)^2) = Sqrt (100+25) = 5x sq root(5)

Circumrference = pi x d = Pi x 5x sq root(5)

D

NiftyNiffler · Answer

Diameter = sqrt((5-(-5))^2+(-2-3)^2) = 5sqrt(5)

Circumference = π*diameter = 5√5π

D

carouselambra · Answer

Distance between (5,-2) and (-5,3) can be calculated as :

\sqrt{(5+5) sq + (-2-3) sq}
\sqrt{125} =5\sqrt{5}

Hence , circumference of the circle = 2*pi*r/2
2*pi*5\sqrt{5} /2

IMO D

SairamRamo · Answer

Radius = Distance between (5, -2) and (-5, 3) *0.5 = sqrt (10^2 + 5^2) * 0.5 = 2.5 * sqrt (5)

Circumference = 2 * pi * Radius = 5 * sqrt (5)

Answer D

gmatcafe · Answer

The diameter of the circle= \sqrt{(5-(-5))^2+(-2-3)^2} =5 \sqrt{5} 
The circumference of the circle= 5\pi\sqrt{5}  D)

GCMEMBER · Answer

Dia = √ 
Here, x1=5, y1=-2, x2=-5, and y2=3
D=√ 
D=√125
D=5√5

Circumference of circle = πD
 = 5√5π

Option D

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