Last visit was: 25 Apr 2026, 13:18 It is currently 25 Apr 2026, 13:18
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,831
Own Kudos:
Given Kudos: 105,886
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,831
Kudos: 811,260
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
bobnil
Joined: 28 May 2017
Last visit: 22 Sep 2023
Posts: 40
Own Kudos:
Given Kudos: 82
Location: India
Posts: 40
Kudos: 39
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
ShankSouljaBoi
Joined: 21 Jun 2017
Last visit: 28 Mar 2026
Posts: 600
Own Kudos:
611
 [1]
Given Kudos: 4,090
Location: India
Concentration: Finance, Economics
GMAT 1: 660 Q49 V31
GMAT 2: 620 Q47 V30
GMAT 3: 650 Q48 V31
GPA: 3.1
WE:Corporate Finance (Non-Profit and Government)
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
Alligator16
Joined: 28 Aug 2018
Last visit: 10 Oct 2022
Posts: 11
Own Kudos:
Given Kudos: 117
Location: India
GMAT 1: 730 Q50 V39
GMAT 1: 730 Q50 V39
Posts: 11
Kudos: 17
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given:
1. ∆ABD & ∆BDC are Right Angle Triangles.
2. AB=3, AD=4, BC=12

To find: Perimeter of ABCD.

Solving: ∆ABD
By using Pythagoras theorem we will get side BD.
BD^2 = AB^2 + AD^2 =25
BD = 5

Solving: ∆BDC
By using Pythagoras theorem we will get side CD.
CD^2 = BD^2 + BC^2 = 169
CD = 13

Perimeter of ABCD: AB+BC+CD+DA = 3+12+13+4= 32

Answer: A

Posted from my mobile device
User avatar
Nipungupta9081
User avatar
School Moderator - INSEAD Masters
Joined: 07 Jan 2020
Last visit: 19 Apr 2026
Posts: 500
Own Kudos:
Given Kudos: 198
Location: India
GPA: 4
WE:Analyst (Accounting)
Posts: 500
Kudos: 274
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the diagram below, AB = 3, AD = 4, and BC = 12. What is the perimeter of the quadrilateral?

(A) 32
(B) 30
(C) 28
(D) 26
(E) 24


Attachment:
2020-12-21_17-17-58.png

IMO A

Triangle ADB is an Right Angle Triangle
3^2 + 4^2 = DB^2
5 = DB

Triangle DBC Right Angle
DB^2 + BC^2 = DC^2
13 = DC


Perimeter = Sum of all sides
DB +BC + CD + DA = 4+3+12+13 = 32
User avatar
Abhishek009
User avatar
Board of Directors
Joined: 11 Jun 2011
Last visit: 17 Dec 2025
Posts: 5,903
Own Kudos:
Given Kudos: 463
Status:QA & VA Forum Moderator
Location: India
GPA: 3.5
WE:Business Development (Commercial Banking)
Posts: 5,903
Kudos: 5,456
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ShankSouljaBoi
3 , 4 , 5

5 , 12 , 13

final ans = 3+4+12+13 = 32 .... A
Using Pythagorean triples form....

Short and cute way to solve this problem in seconds, Kudos added :ok :ok :ok :student_man: :student_man: :student_man:
Moderators:
Math Expert
109831 posts
Tuck School Moderator
852 posts