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B.

Given that the figure is a rhombus and two of the diagonals are given (8,12), we can find out the legs of a right triangle. (4,6). Find the third side via Pythagoras theorem = 2 sqrt(13)

There are 4 sides. Multiple 2 sqrt(13) by 4 => 8 sqrt(13)
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Bunuel
In the figure below, ABCD is a rhombus, a parallelogram with sides of equal length. If the diagonals AC and BD bisect each other and are 12 centimeters and 8 centimeters long, respectively, what is the perimeter of the rhombus, in centimeters?


(A) 20
(B) \(8 \sqrt{13}\)
(C) 40
(D) \(16 \sqrt{13}\)
(E) It cannot be determined.

Attachment:
2020-12-30_20-57-02.png

Diagonals of a Rhombus bisect each other making 90-degree angles.

So, a side (AB, or BC, or CD, or AD) of the rhombus will be the hypotenuse of the right triangle made with half of the diagonals.
\((AB)^2=4^2+6^2\) [ 4 and 6 are the halves of the diagonals]

\((AB)^2=16+36\)

\(AB=\sqrt{52}\)

\(AB=2\sqrt{13}\)

The perimeter \(= 4*2\sqrt{13}=8\sqrt{13}\) As each side of a rhombus is equal.

The answer is \(B\)
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It hasn't been given that the diagonals are perpendicular bisectors. Can someone please help me understand why we are assuming that to be true?
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It hasn't been given that the diagonals are perpendicular bisectors. Can someone please help me understand why we are assuming that to be true?
Property of rhombus. So, it wont be given in the question, one must know the properties of 2D geometry. Thank you.

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rs999
It hasn't been given that the diagonals are perpendicular bisectors. Can someone please help me understand why we are assuming that to be true?

• The diagonals of a rhombus always bisect each other at 90°.

Check more in Math: Polygons.

Hope it helps.
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