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If An=7n−1, what is the units digit of A33?

Cyclicity of 7 is 4 with unit digits 7, 9, 3, 1 of pwers 1, 2, 3,and 4 of 7
7^33 will have same unit digit as 7 so unit digit of the asked term will be 7-1= 6

Option C is the correct choice
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\(A_{n} = 7^n − 1\)

To find \(A_{33}\) we will replace n with 33 in \(A_{n} = 7^n − 1\)

=> \(A_{33} = 7^{33} − 1\)
[ Watch this video to MASTER FUNCTIONS ]

To find the units' digit of \(7^{33}\), we need to find the cycle of units' digit of power of 7

\(7^1\) units’ digit is 7
\(7^2\) units’ digit is 9
\(7^3\) units’ digit is 3
\(7^4\) units’ digit is 1
\(7^5\) units’ digit is 7

=> The power repeats after every \(4^{th}\) power
=> Cycle of units' digit of power of 7 = 4
=> We need to divide the power by 4 and check the remainder

33 when divided by 4 gives 1 remainder
=> Units' digit of \(7^{33}\) = Units' digit of \(7^1\) = 7

=> Units' digit of \(7^{33} − 1\) = 7 - 1 = 6

So, Answer will be C
Hope it helps!

Watch the following video to MASTER Units Digit

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