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04 Aug 2021, 01:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
52% (01:32) correct
48%
(01:59)
wrong
based on 85
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The base of pyramid P is an isosceles right triangle whose leg is 3. If the height of P is 4, what is the volume of P?
A. 36
B. 18
C. 12
D. 8
E. 6
Attachment:
1.png [ 6.01 KiB | Viewed 2525 times ]
04 Aug 2021, 02:00
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Explanation:
Volume of a pyramid = 1/3×Base Area×Height
height base = leg of pyramid = 3
Base area = 1/2 x height base x leg of pyramid
= 1/2 x 3 x 3
= 9/2
Volume of a pyramid = 1/3 x 9/2 x 4
= 2x3 = 6
IMO-E
Volume of a pyramid = 1/3×Base Area×Height
height base = leg of pyramid = 3
Base area = 1/2 x height base x leg of pyramid
= 1/2 x 3 x 3
= 9/2
Volume of a pyramid = 1/3 x 9/2 x 4
= 2x3 = 6
IMO-E
04 Aug 2021, 10:07
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Volume of pyramid = \(\frac{1}{3}\)* base area* height
Base area= \(\frac{1}{2}\)*3*3
Height = 4
Volume of pyramid =\(\frac{1}{3}*\frac{1}{2}\)*3*3*4 = 6
Option (E) is correct
Base area= \(\frac{1}{2}\)*3*3
Height = 4
Volume of pyramid =\(\frac{1}{3}*\frac{1}{2}\)*3*3*4 = 6
Option (E) is correct
Bunuel
