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22 Oct 2021, 03:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
62% (03:12) correct
38%
(02:21)
wrong
based on 45
sessions
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A motor scooter has an empty rectangular gas tank with dimensions of 4 * 8 * 10 inches. Then thank is filled completely with gasoline form a cylindrical container with a diameter of 8 inches. Of the gasoline fills the cylindrical container to a height of 20 inches before the gas tank is filled, how high, in inches, is the gasoline in the cylindrical container after the tank is filled?
(A) \(\frac{20}{π}\)
(B) \( 80 ( 4π - 3)\)
(C) 10
(D) \(\frac{5 (π - 1)}{4}\)
(E) \(\frac{20 (π - 1)}{π}\)
(A) \(\frac{20}{π}\)
(B) \( 80 ( 4π - 3)\)
(C) 10
(D) \(\frac{5 (π - 1)}{4}\)
(E) \(\frac{20 (π - 1)}{π}\)
happypuppy
GMAT 1: 720 Q50 V38 (Online)
Posts: 203
22 Oct 2021, 03:59
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Bunuel
Volume rectangular gas tank = 4 * 8 * 10 - (1)
Equivalent vol of cylindrical tank = π 4 * 4 height - (2)
Equating (1) and (2)
We get, height = 20/ π
Remaining height after tank is filled = 20 - 20/π or 20 (π - 1)/π.
Option (E)
22 Oct 2021, 05:16
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Rectangular gas tank volume (RT) = 320
Cylindrical container volume (CC) = π x 4^2 x 20
Remaining Volume after filling RT = CC - RT = 320π - 320
Remaining Height = (320π - 320) / π x 16 = 20(π - 1)/π
Option E
Poorly worded question. Bunuel , please check the question language.
Cylindrical container volume (CC) = π x 4^2 x 20
Remaining Volume after filling RT = CC - RT = 320π - 320
Remaining Height = (320π - 320) / π x 16 = 20(π - 1)/π
Option E
Poorly worded question. Bunuel , please check the question language.
