If x^2 x^3 x, which of the following is NOT a possible value of x?

Question

If  x^2>x^3>x , which of the following is NOT a possible value of x?

(A)  -\frac{1}{8}

(B)  -\frac{1}{3}

(C)  -\frac{2}{7}

(D)  -\frac{7}{6}

(E)  -\frac{6}{7}

Kalpit1212 · Answer

There are only two possibilities where x^3>x (i) where x>1 and (ii) where -11, x^2

errorlogger · Answer

x^2>x^3>x Divide the whole equation by x^2 : 1>x>\frac{1}{x} \frac{1}{x}

SohGMAT2020 · Answer

Since,  x^2>x^3>x

Any negative fraction will satisfy the condition, So we eliminate A, B , and C

for D, x^3 < x , so this value is not possible

for E, since 6/7 is less than 1, its square and cube will be smaller than x, hence this value is also not possible.

I find D and E both correct

1616 · Answer

Hello  Bunuel ,

I found both D and E as correct answers, Please clarify, I

If I am right, please hit kudos!!

Bunuel · Answer

Fixed option E. Thank you!

If x^2 > x^3 >x, which of the following is NOT a possible value of x?