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13 Dec 2021, 03:15
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Difficulty:
55%
(hard)
Question Stats:
68% (02:26) correct
32%
(02:32)
wrong
based on 319
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A and B are two alloys of copper and tin prepared by mixing the respective metals in ratio of 5:3 and 5:11 respectively. If the alloy A and B are mixed to form a third alloy C with an equal proportions of copper and tin what is the ration of alloys A and B In the new alloy C?
A 3:5
B 4:5
C 3:2
D 2:3
E 15:17
A 3:5
B 4:5
C 3:2
D 2:3
E 15:17
21 Dec 2021, 10:54
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Given:
A B C= A+B
Copper 5a 5b 5a + 5b
Tin 3a 11b 3a + 11b
Total 8a 16b
In C, the ratio of Copper and Tin is Equal.
So 5a + 5b = 3a +11b --> 2a = 6b --> a/b =3/1 .........(1)
Now we are asked what is the ratio of alloys A and B in new alloy C.
So we need Alloy A/ Alloy B --> (8a)/(16b) i.e. we need to find a/2b and using (1) we get
a/2b = 1/2 * a/b = 1/2 * 3/1 = 3/2.
A B C= A+B
Copper 5a 5b 5a + 5b
Tin 3a 11b 3a + 11b
Total 8a 16b
In C, the ratio of Copper and Tin is Equal.
So 5a + 5b = 3a +11b --> 2a = 6b --> a/b =3/1 .........(1)
Now we are asked what is the ratio of alloys A and B in new alloy C.
So we need Alloy A/ Alloy B --> (8a)/(16b) i.e. we need to find a/2b and using (1) we get
a/2b = 1/2 * a/b = 1/2 * 3/1 = 3/2.
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General Discussion
13 Oct 2022, 20:47
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A and B are two alloys of copper and tin prepared by mixing the respective metals in ratio of 5:3 and 5:11 respectively. If the alloy A and B are mixed to form a third alloy C with an equal proportions of copper and tin what is the ration of alloys A and B In the new alloy C?
A 3:5
B 4:5
C 3:2
D 2:3
E 15:17
Alloy A ratio = 5:3 Copper = 5/8 = 10/16
Alloy B ratio = 5:11 Copper = 5/16 = 5/16
Final Alloy C = 1:1 Copper = 1/2 = 8/16
Make denominator common
Copper average in alloy c = 8
Using alligation
POV of copper
A = 10 B = 5
C = 8
(Average)
8 - 5 10 - 8
= 3 : 2
C
A 3:5
B 4:5
C 3:2
D 2:3
E 15:17
Alloy A ratio = 5:3 Copper = 5/8 = 10/16
Alloy B ratio = 5:11 Copper = 5/16 = 5/16
Final Alloy C = 1:1 Copper = 1/2 = 8/16
Make denominator common
Copper average in alloy c = 8
Using alligation
POV of copper
A = 10 B = 5
C = 8
(Average)
8 - 5 10 - 8
= 3 : 2
C
