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17 Aug 2022, 07:52
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E
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Difficulty:
75%
(hard)
Question Stats:
52% (01:57) correct
48%
(01:59)
wrong
based on 139
sessions
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If regular polygon P has between 50 and 60 possible diagonals, how many sides does polygon P have?
A. 8
B. 9
C. 10
D. 11
E. 12
A. 8
B. 9
C. 10
D. 11
E. 12
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17 Aug 2022, 08:15
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for a n-sided polygon the number of diagonals can be determined by
n*( n-3) / 2
here polygon P has between 50 and 60 possible diagonals
n= 12
(12 * 9)/2 ; 54
OPTION E
n*( n-3) / 2
here polygon P has between 50 and 60 possible diagonals
n= 12
(12 * 9)/2 ; 54
OPTION E
BrentGMATPrepNow
16 Sep 2022, 00:49
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The number of diagonals of a n-sided polygon is given by \( \frac{n(n-3)}{2}\)
50 < \( \frac{n(n-3)}{2}\) < 60
Multiply both sides by 2
100 < n (n-3) < 120
We can pick the highest value in the options to check if it satisfy the equation
n = 12
100 < 12 * 9 < 120
100 < 108 < 120 - Yes
Option E
50 < \( \frac{n(n-3)}{2}\) < 60
Multiply both sides by 2
100 < n (n-3) < 120
We can pick the highest value in the options to check if it satisfy the equation
n = 12
100 < 12 * 9 < 120
100 < 108 < 120 - Yes
Option E
