Last visit was: 23 Apr 2026, 18:09 It is currently 23 Apr 2026, 18:09
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,872
 [40]
1
Kudos
Add Kudos
39
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
810,872
 [9]
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,872
 [9]
3
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
General Discussion
User avatar
gmatophobia
User avatar
Quant Chat Moderator
Joined: 22 Dec 2016
Last visit: 19 Apr 2026
Posts: 3,173
Own Kudos:
11,457
 [9]
Given Kudos: 1,862
Location: India
Concentration: Strategy, Leadership
Posts: 3,173
Kudos: 11,457
 [9]
7
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
810,872
 [3]
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,872
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
gmatophobia
Bunuel
What is the remainder when 11^1 + 11^2 + 11^3 + ... + 11^11 is divided by 22 ?

A. 0
B. 1
C. 10
D. 11
E. 21

 


Enjoy this brand new question we just created for the GMAT Club Tests.

To get 1,600 more questions and to learn more visit: user reviews | learn more

 



Hint: this question has 30 sec solution. Do not overcomplicate it.

Rem(\(\frac{11(1 + 11 + 11^2 + ..... + 11^{10}) }{ 11 * 2}\))

We can cancel 11 from numerator and denominator

Rem(\(\frac{1 + 11 + 11^2 + ..... + 11^{10} }{ 2}\))

\(1 + 11 + 11^2 + ..... + 11^{10}\) are 11 terms (\(11^0\) to \(11^{10}\)), so the sum is odd.

Remainder(odd / 2) = 1

As we cancelled 11 initially, net remainder = 1 * 11 = 11

Option D

P.S. Not sure if this was the 30 second solution :P

That's close to what I had in mind and basically uses the same logic. :thumbsup: :thumbsup: :thumbsup:
User avatar
AritraKundu
Joined: 05 Feb 2017
Last visit: 23 Jul 2023
Posts: 15
Own Kudos:
9
 [2]
Given Kudos: 80
Posts: 15
Kudos: 9
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi, here is my working but please let me know if my thought process is correct.

11^1+11^2+11^3+....+11^11/22 can be broken into
11^1/22, 11^2/22,11^3/22........11^11/22
In all cases 11 will be the remainder
So, 11+11+11+....+11/22=11*11/22=121/22
The remainder is 11
User avatar
hardikpujara
Joined: 08 Feb 2020
Last visit: 19 Mar 2024
Posts: 6
Own Kudos:
Given Kudos: 22
Posts: 6
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
gmatophobia
Bunuel
What is the remainder when 11^1 + 11^2 + 11^3 + ... + 11^11 is divided by 22 ?

A. 0
B. 1
C. 10
D. 11
E. 21

 


Enjoy this brand new question we just created for the GMAT Club Tests.

To get 1,600 more questions and to learn more visit: user reviews | learn more

 



Hint: this question has 30 sec solution. Do not overcomplicate it.

Rem(\(\frac{11(1 + 11 + 11^2 + ..... + 11^{10}) }{ 11 * 2}\))

We can cancel 11 from numerator and denominator

Rem(\(\frac{1 + 11 + 11^2 + ..... + 11^{10} }{ 2}\))

\(1 + 11 + 11^2 + ..... + 11^{10}\) are 11 terms (\(11^0\) to \(11^{10}\)) and each term is odd, so the sum of 11 odd terms is odd.

Remainder(odd / 2) = 1

As we cancelled 11 initially, net remainder = 1 * 11 = 11

Option D

P.S. Not sure if this was the 30 second solution :P

not sure about
As we cancelled 11 initially, net remainder = 1 * 11 = 11
User avatar
gmatophobia
User avatar
Quant Chat Moderator
Joined: 22 Dec 2016
Last visit: 19 Apr 2026
Posts: 3,173
Own Kudos:
11,457
 [13]
Given Kudos: 1,862
Location: India
Concentration: Strategy, Leadership
Posts: 3,173
Kudos: 11,457
 [13]
9
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
hardikpujara


not sure about
As we cancelled 11 initially, net remainder = 1 * 11 = 11

The general rule is - "Whenever we cancel a common factor from the numerator and denominator , that factor needs to be accounted for in the final remainder"

Example : Say we want to find the remainder of Reminder(\(\frac{22}{55}\))

By logic we know that the remainder is 22.

Let's try to do this mathematically -

Remainder(\(\frac{22}{55}\))

We can cancel 11 from both the numerator and the denominator and arrive at a reduced fraction \(\frac{2}{5}\)

The remainder when 2 is divided by 5 is 2.

So is the remainder when \(\frac{22}{55}\) = 2 ? No !

That's because we didn't factor the 11 that we cancelled out initially.

The net remainder = 2 * 11 = 22.

Hope it's clear !
User avatar
khumoyuns
Joined: 04 Sep 2020
Last visit: 03 Feb 2025
Posts: 14
Own Kudos:
Given Kudos: 94
Location: Uzbekistan
GMAT 1: 770 Q50 V44
GPA: 3.79
WE:Law (Consulting)
GMAT 1: 770 Q50 V44
Posts: 14
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
You may break this number down to:

(11 + 11*(11+11^2...+11^10))/22

Expression in the inner bracket should be even (as it is the sum of an even number of odd numbers);
11 * by even number should be divisible by 22;

You will end up with q (some integer) + 11/22. Thus, the remainder should be 11

Hope the above is helpful
User avatar
sachi-in
Joined: 12 Oct 2023
Last visit: 07 Apr 2026
Posts: 120
Own Kudos:
Given Kudos: 146
Posts: 120
Kudos: 338
Kudos
Add Kudos
Bookmarks
Bookmark this Post
What is the remainder when 11^1 + 11^2 + 11^3 + ... + 11^11 is divided by 22 ?

A. 0
B. 1
C. 10
D. 11
E. 21

11 + 11^2( 1 + 11 ) + 11^4( 1 + 11 ) + ..... + 11^10( 1 + 11 )

11 + 12 * ( 11^2 + ... 11^10)

Highlighted portion multiple of 22

remainder 11
User avatar
Oppenheimer1945
Joined: 16 Jul 2019
Last visit: 21 Apr 2026
Posts: 785
Own Kudos:
663
 [1]
Given Kudos: 236
Location: India
GMAT Focus 1: 645 Q90 V76 DI80
GPA: 7.81
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Odd terms hence Expression =11(odd no)=11(2k+1)=22k+11

Leaves remainder of 11 when divided by 22

Posted from my mobile device
User avatar
Yuvrajbangatrader
Joined: 22 Mar 2024
Last visit: 03 Sep 2025
Posts: 5
Own Kudos:
Given Kudos: 3
Posts: 5
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
11/22>> remainder is 11
121/22>> remainder is 11
Pattern "Might" follow till 11^11
Therefore 11+11+11+11+...=121
and 121/22>> remainder 11
User avatar
sujoykrdatta
Joined: 26 Jun 2014
Last visit: 22 Apr 2026
Posts: 587
Own Kudos:
1,191
 [1]
Given Kudos: 14
Status:Mentor & Coach | GMAT Q51 | CAT 99.98
GMAT 1: 740 Q51 V39
Expert
Expert reply
GMAT 1: 740 Q51 V39
Posts: 587
Kudos: 1,191
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
What is the remainder when 11^1 + 11^2 + 11^3 + ... + 11^11 is divided by 22 ?

A. 0
B. 1
C. 10
D. 11
E. 21

M40-04

Hint: this question has 30 sec solution. Do not overcomplicate it.

Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!

There are 11 terms. If we ignore the first term, we have 10 terms, all divisible by 11 and all odd
Thus, sum of the last 10 terms is divisible by 11 and also by 2 i.e. also by 22

Thus, the remainder is simply the first term, i.e. 11 when divided by 22
User avatar
shubhim20
Joined: 03 Feb 2025
Last visit: 27 Nov 2025
Posts: 108
Own Kudos:
Given Kudos: 156
Posts: 108
Kudos: 3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
thanks you explained it so well
gmatophobia


The general rule is - "Whenever we cancel a common factor from the numerator and denominator , that factor needs to be accounted for in the final remainder"

Example : Say we want to find the remainder of Reminder(\(\frac{22}{55}\))

By logic we know that the remainder is 22.

Let's try to do this mathematically -

Remainder(\(\frac{22}{55}\))

We can cancel 11 from both the numerator and the denominator and arrive at a reduced fraction \(\frac{2}{5}\)

The remainder when 2 is divided by 5 is 2.

So is the remainder when \(\frac{22}{55}\) = 2 ? No !

That's because we didn't factor the 11 that we cancelled out initially.

The net remainder = 2 * 11 = 22.

Hope it's clear !
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 23 Apr 2026
Posts: 5,986
Own Kudos:
Given Kudos: 163
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,986
Kudos: 5,858
Kudos
Add Kudos
Bookmarks
Bookmark this Post
What is the remainder when 11^1 + 11^2 + 11^3 + ... + 11^11 is divided by 22 ?

The remainder when 11^1 is divided by 22 = 11
The remainder when 11^2 is divided by 22 = 11
The remainder when 11^3 is divided by 22 = 11
...

The remainder when 11^11 is divided by 22 = 11

The remainder when 11^1 + 11^2 + 11^3 + ... + 11^11 is divided by 22
= The remainder when 11 + 11 + 11.... 11 times is divided by 22
= The remainder when 11*11 = 11^2 is divided by 22 = 11

IMO D
Moderators:
Math Expert
109785 posts
Tuck School Moderator
853 posts