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Difficulty:
5%
(low)
Question Stats:
94% (01:07) correct
6%
(01:36)
wrong
based on 87
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At a certain college there are 4 freshmen for every 3 sophomores and 15 sophomores for every 12 juniors. If there are 24 juniors, how many freshmen are there?
(A) 4
(B) 15
(C) 30
(D) 40
(E) 60
How to solve this using plug in?
(A) 4
(B) 15
(C) 30
(D) 40
(E) 60
How to solve this using plug in?
08 Jul 2023, 00:55
Kudos
Bookmarks
Based on the data,
Ratio of Freshmen(F) to Sophomore (S) is 4:3
Similarly for S and Juniors it is 15:12
Now we have 24 Juniors. For every 12 Juniors, its given to have 15 Sophomers
Hence for 24 Juniors, 30 Sophomors present (Direct Relation)
Now for every 3 sophomores, 4 Freshmen present
So for 30 sophomore (3x10) there will be (4x10) 40 freshmen
Ratio of Freshmen(F) to Sophomore (S) is 4:3
Similarly for S and Juniors it is 15:12
Now we have 24 Juniors. For every 12 Juniors, its given to have 15 Sophomers
Hence for 24 Juniors, 30 Sophomors present (Direct Relation)
Now for every 3 sophomores, 4 Freshmen present
So for 30 sophomore (3x10) there will be (4x10) 40 freshmen
08 Jul 2023, 07:53
Kudos
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Given for every 12 J, you have 15 S. And for every 3 S you have 4 F. In such type of ratio problems, equate common linking element in order to solve.
In other words:
J:S = 12:15 ....(1)
S:F = 3:4 ......(2)
Since S is common linking element, equate S in both equations, i.e. multiply eq. 2 by factor of 5.
Now,
J:S = 12:15
and S:F = 15:20
So J:S:F = 12:15:20
Hence if J = 24, then S = 30 and F = 40.
Therefore C is the correct answer.
In other words:
J:S = 12:15 ....(1)
S:F = 3:4 ......(2)
Since S is common linking element, equate S in both equations, i.e. multiply eq. 2 by factor of 5.
Now,
J:S = 12:15
and S:F = 15:20
So J:S:F = 12:15:20
Hence if J = 24, then S = 30 and F = 40.
Therefore C is the correct answer.
manali_02
