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andrewjohn8
­Which of the following is equal to \(\frac{12 + \sqrt{28}}{\sqrt{9 + 7}­}\)?

A. \(\frac{12 + 2\sqrt{7}}{3+\sqrt{7}}\)

B. \(3+2\sqrt{7}\)

C. \(3+\sqrt{7}\)

D. \(3 + \frac{\sqrt{7}}{2}\)

E. \(6\)

­
­

\(\frac{12 + \sqrt{28}}{\sqrt{9 + 7}­}=\)

\(=\frac{12 + 2\sqrt{28}}{\sqrt{16}­}=\)

\(=\frac{12 + 2\sqrt{28}}{4}=\)

\(=3+\frac{\sqrt{28}}{2}\).
Answer: D.

P.S. andrewjohn8, thank you!
P.P.S. Is this CR question also from GMAT Prep Focus mocks?
Where did the "2" come from?
Attachment:
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Bunuel
andrewjohn8
­Which of the following is equal to \(\frac{12 + \sqrt{28}}{\sqrt{9 + 7}­}\)?

A. \(\frac{12 + 2\sqrt{7}}{3+\sqrt{7}}\)

B. \(3+2\sqrt{7}\)

C. \(3+\sqrt{7}\)

D. \(3 + \frac{\sqrt{7}}{2}\)

E. \(6\)

­
­

\(\frac{12 + \sqrt{28}}{\sqrt{9 + 7}­}=\)

\(=\frac{12 + 2\sqrt{28}}{\sqrt{16}­}=\)

\(=\frac{12 + 2\sqrt{28}}{4}=\)

\(=3+\frac{\sqrt{28}}{2}\).

Answer: D.
Where did the "2" come from?

That was a typo. Edited:



\(\frac{12 + \sqrt{28}}{\sqrt{9 + 7}­}=\)

\(=\frac{12 + 2\sqrt{7}}{\sqrt{16}­}=\)

\(=\frac{12 + 2\sqrt{7}}{4}=\)

\(=3+\frac{\sqrt{7}}{2}\).

Answer: D.
Attachment:
GMAT-Club-Forum-4bx8h807.png
GMAT-Club-Forum-4bx8h807.png [ 11.9 KiB | Viewed 2103 times ]
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