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Consider distance to be 180 km,

When going 60kmph it takes 3 hrs , when going 45 kmph it takes 4 hrs.
So 1 hr of stoppage for every 4 hrs. So for every 1 hr it is 15 mins.
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D= ST
t1 is time with 60Km/h
t2 is stoppage time
x= 60(t1)
x = 45(t1+t2)
60(t1) = 45(t1+t2)
4t1 = 3t1 + 3t2
t1 = 3t2
t2 = t1/3
subsituting options
t2 = 15
then t1 =45
60(t1) = 45(t1+t2)
this equation satisifies
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Let, distance= LCM of 60,45= 180

Distance.....Speed......Time
180 km.......60 kmph.....T
180 km.......45 kmph.....t
T= 180/60= 3 hrs
t= 180/45= 4 hrs
She stopped for 1 hr in 4 hrs, so she stopped for 15 mins each hour during journey.

Answer: A
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Bunuel
Without stoppage, Kalpana travel’s bus travels a certain distance with an average speed of 60 km/hr, and with stoppage, it covers the same distance with an average speed of 45 km/hr. On an average, how many minutes per hour does the bus stop during the journey ?

(A) 15 min­
(B) 20 min
(C) 25 min
(D) 30 min
(E) 45 min


­
Without stoppages, Kalpana travels a distance of 60 km in 1 hr = 60 mins.

With stoppages , she travels at an average speed of 45 kmph. And covers a distance of 45 km in 1 hour.

Usually, this 45 km is covered in 45 mins. This means, the balance 15 mins is spent in stoppages.

Option A
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Distance is same and Distance = Speed* Time

60 * T = 45 * t

T = 3/4 t => t - t/4

t= 1 hour (Time during stoppage)
T = 45 min so 15 min stoppage per hour.

A is the answer
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