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Bunuel
If 0 < x < 1, which of the following is the greatest?

A. \(x^{(-\frac{1}{2})}\)

B. \(x^0\)

C. \(x^{(\frac{1}{2})}\)

D. \(x^1\)

E. \(x^2\)


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Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
A number x between 0 and 1 is a fraction of the form p/q , where denominator q > numerator p.

let’s look Into the options

A. \(x^{(-\frac{1}{2})}\)

x^-(1/2) =. 1/ (x)^1/2 = 1/sqrt(x) = sqrt (q/p) .

With denominator (q) greater than numerator (p). Sqrt (q/p) provides a value greater than 1.

B. \(x^0\)

Any number to the power of zero “0” is 1.

C. \(x^{(\frac{1}{2})}\)

square root of a number less than 1 cannot be greater than 1.

D. \(x^1\)

This value is same as x, and lies between 0 < x <1.

E. \(x^2\)

When we square a fraction, the value becomes less than the fraction.

Hence, the greatest value is Option A
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Given 0<x<1
taking x to be 1/2 and evaluating all options

A) x^(-1/2) gives sqrt(2) = 1.414
B) x^0 gives = 1
C) x^(1/2) gives = 1/sqrt(2)
D)x^1 gives 0.5
E)x^2 gives 0.25

Hence Option A is the answer
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Always a classic!

Another way to think about this one is to use the property of exponents for numbers between 0 and 1.
\(0 < x < 1,\; m > n \implies x^m < x^n\)

Identify all the exponents in the options.
\(\text{Exponents are } -\frac{1}{2},\;0,\;\frac{1}{2},\;1,\;2\)

Arrange these exponents from largest to smallest.
\(2 > 1 > \frac{1}{2} > 0 > -\frac{1}{2}\)

Apply the exponent property to compare the expressions.
\(x^2 < x^1 < x^{\frac{1}{2}} < x^0 < x^{-\frac{1}{2}}\)

Answer A

Hope this helps!
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