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If \(x = 2^2 * 7^4 \), and \(y = 2^{12}\), and \(z= 2^4*5^4\), which of the following is true?

A. x > y > z
B. y > x > z
C. x > z > y
D. y > z > x
E. z > x > y

\(x = 2^2 * 7^4 = 2^2 * (49)^2 = 98^2\)

\(y= 2^{12} = (2^6)^2 = 64^2\)

\(z = 2^4 * 5^4 = 10^4 = 100^2\)

So, \((z=2^4 * 5^4) > (x=2^2 * 7^4) > (y=2^{12})\)

Answer: E.
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x = (2^2)*(7^4) ~ 2^2*2^12 (actual value of x will be a little less than this)
y = 2^12
From above we can see that x>y

z = 2^2*5^4 = 10^2*5^2 = 50^2
x=2^2*7^4 = 4*49^2
from above z>x

So, z>x>y
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x = 2^2 * 7^4
x = 14^2 * 7^2
x = 196 *49
it must be less than 10000 because if we consider 200*50 = 10000. but here we have 196*49. so it mist be less than that.

Y= 2^12
Y = 1024 * 2^2
Y= 4096

Z= 10^4
Z= 10,000

so the relation that is built on this is Z>X>Y
option E
pegasus21
If \(x = 2^2 * 7^4 \), and \(y = 2^{12}\), and \(z= 2^4*5^4\), which of the following is true?

A. x > y > z
B. y > x > z
C. x > z > y
D. y > z > x
E. z > x > y




Here, particularly between x and y, which one is greater?
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