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Solving the inequality |3 - x| < x + 5.
First, note that for the inequality to hold, x + 5 must be positive, so x > -5.
Case 1: 3 - x ≥ 0, meaning x ≤ 3
3 - x < x + 5, giving -2 < 2x, so x > -1.
Combined with x ≤ 3, this gives -1 < x ≤ 3.
Case 2: 3 - x < 0, meaning x > 3
-(3 - x) < x + 5, giving x - 3 < x + 5, giving -3 < 5, which is always true.
Combined with x > 3, this gives x > 3.
Overall solution: x > -1
Now checking the three statements:
Statement I: x < 0. This is possible since x can be any value between -1 and 0, for example x = -0.5. This MAY be true.
Statement II: x < -1. This is never true since the solution requires x > -1. This cannot be true.
Statement III: x > 2. This is possible since x can be greater than 2. This MAY be true.
The answer is D — I and III only.
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|3 − x| < x + 5

Case 1: 3 − x ≥ 0 → x ≤ 3

Then: 3 − x < x + 5
→ 3 - x < x + 5
→ -2 < 2x
→ x > -1

So from this case: -1 < x ≤ 3

Case 2: 3 − x < 0 → x > 3
Then: |3 − x| = x − 3
x − 3 < x + 5 → always true
So: x > 3

Combine both:
x > -1

Now check statements:

I. x < 0 → possible (e.g., x = -0.5)
II. x < -1 → not possible
III. x > 2 → possible (e.g., x = 3)

Ans: D. (I and III only)

ExpertsGlobal5
If |3 – x| < x + 5, which of the following may be true about x?

I. x < 0
II. x < –1
III. x > 2

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III

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ExpertsGlobal5
If |3 – x| < x + 5, which of the following may be true about x?

I. x < 0
II. x < –1
III. x > 2

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III
D is the correct answer choice.

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