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20 May 2026, 01:04
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
20% (00:40) correct
80%
(03:03)
wrong
based on 5
sessions
History
Date
Time
Result
Not Attempted Yet
Vicente bought two T-shirts for the same price. One had been marked down by 75%. If he had bought the two T-shirts for their regular prices, he would have paid three times as much. By what percent had the other T-shirt been marked down?
(A) 50%
(B) 58 \(\frac{1}{3}\)%
(C) 60%
(D) 62 \(\frac{1}{2}\)%
(E) 66 \(\frac{2}{3}\)%
(A) 50%
(B) 58 \(\frac{1}{3}\)%
(C) 60%
(D) 62 \(\frac{1}{2}\)%
(E) 66 \(\frac{2}{3}\)%
20 May 2026, 05:46
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Answer: (A) 50%
This is a Percent and Interest problem that catches a lot of people — the trap is jumping to the weighted average or trying to set up some formula before just assigning a clean variable.
Let P = the price Vicente actually paid for each shirt (they're the same, so both cost P).
1. Shirt 1 was marked down 75%, meaning he paid 25% of its regular price.
So P = 0.25 * R1 → R1 = 4P.
2. Shirt 2 was marked down by some unknown percent x.
So P = (1 - x) * R2.
3. "If he had bought the two T-shirts at their regular prices, he would have paid three times as much."
He actually paid P + P = 2P total. Three times that is 6P.
So R1 + R2 = 6P.
4. Plug in R1 = 4P:
4P + R2 = 6P → R2 = 2P.
5. Now use R2 in the equation for Shirt 2:
P = (1 - x) * 2P
1/2 = 1 - x
x = 1/2 = 50%.
The trap here is (C) 60% — people sometimes subtract 75% from some made-up total and arrive there. I fell for a version of this the first time I saw it. The key move is just calling the common sale price P and working from there — no system of equations, no guessing.
Answer: (A)
This is a Percent and Interest problem that catches a lot of people — the trap is jumping to the weighted average or trying to set up some formula before just assigning a clean variable.
Let P = the price Vicente actually paid for each shirt (they're the same, so both cost P).
1. Shirt 1 was marked down 75%, meaning he paid 25% of its regular price.
So P = 0.25 * R1 → R1 = 4P.
2. Shirt 2 was marked down by some unknown percent x.
So P = (1 - x) * R2.
3. "If he had bought the two T-shirts at their regular prices, he would have paid three times as much."
He actually paid P + P = 2P total. Three times that is 6P.
So R1 + R2 = 6P.
4. Plug in R1 = 4P:
4P + R2 = 6P → R2 = 2P.
5. Now use R2 in the equation for Shirt 2:
P = (1 - x) * 2P
1/2 = 1 - x
x = 1/2 = 50%.
The trap here is (C) 60% — people sometimes subtract 75% from some made-up total and arrive there. I fell for a version of this the first time I saw it. The key move is just calling the common sale price P and working from there — no system of equations, no guessing.
Answer: (A)
20 May 2026, 06:59
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Answer: (B)
Let S = the original/regular price of each of the T shirts.
Hence, Actual cost price for 2 T-shirts = 2*S
Now, the price paid by Vicente for 2 T-shirts:
For 1st T-shirt= (1-0.75%)*S= 0.25%*S
For 2nd T-shirt, let x% be the percentage by which the other T-shirt was marked down, hence price paid for 2nd T-shirt= (1-x%)*S
Now, looking at the scenario- "If he had bought the two T-shirts at their regular prices, he would have paid three times as much"
The equation becomes-->
2*S= 3*[(0.25*S)+(1-x%)*S]
Solving the above equation, we get x= 58(1/3)%
Answer: (B)
Let S = the original/regular price of each of the T shirts.
Hence, Actual cost price for 2 T-shirts = 2*S
Now, the price paid by Vicente for 2 T-shirts:
For 1st T-shirt= (1-0.75%)*S= 0.25%*S
For 2nd T-shirt, let x% be the percentage by which the other T-shirt was marked down, hence price paid for 2nd T-shirt= (1-x%)*S
Now, looking at the scenario- "If he had bought the two T-shirts at their regular prices, he would have paid three times as much"
The equation becomes-->
2*S= 3*[(0.25*S)+(1-x%)*S]
Solving the above equation, we get x= 58(1/3)%
Answer: (B)
