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1.... 10/100*X + 15/100*Y = 38 (protein)

2.... X + Y = 300 (Total Mix)

Solve for X = 140
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ju_1
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 150
(B)145
(C) 100
(D) 160
(E) 140

x(10%) y(15%)
38%
23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X
----------- = --------------
(23+28) 300

23/51 = x/300

x = 23 * 300
------------
51

hence x is approximately equal to 139.8

hence the answer is E
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X+Y = 300

0.1X + 0.15Y = 38

X=140
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start with some numbers.
if x = 100, then y=200
protien from x = 10 and from y = 30 . total protein = 40. greater.. hmm. it means y is somewhat more than it should be. this implies x > 100.
x= 150 , then y=150
protein from x = 15 and from y = 22.5 total = 37.5..lesser
so answer is between 100 and 150 . if we see there are two choices 140 and 145. which one it should be?
well after increasing x by 50 we notice that we reduced total protein from 40 to 37.5 means 2.5. We just need to reduce the protein by 2.

Let us try 140 with this, protein from x = 14 , protein from y = 16+8 = 24. total = 38. this works!
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Take equal proportion to have an idea of ratio,150 each. X will give 15g, Y will give 22.5g which is closer to 38 (37.5)
A little thought on the options D& E will give us E as the answer


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10/100 (x) + 15/100 (300-x) = 38

10/100 (x) + 45 - 15/100 (x) = 38

-5/100 (x) = -7 --> x= 140
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ju_1
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140

We can let x = the amount of X and y = the amount of Y. Let’s create two equations:

x + y = 300

y = 300 - x

And

0.1x + 0.15y = 38

0.1x + 0.15(300 - x) = 38

0.1x + 45 - 0.15x = 38

7 = 0.05x

140 = x

Answer: E
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ju_1
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140

Food X has 10% protein
Food Y has 15% protein

The mix has (38/300)*100 = (38/3)% protein (so this is the average protein)

wX/wY = (15 - 38/3) / (38/3 - 10) = 7/8

So food X and food Y are mixed in the ratio 7:8 in the 300 gms of mix.
Food X must be 140 gms and food Y must be 160 gms.

Answer (E)
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10/100*X + 15/100*Y = 38 (protein)

X + Y = 300 (Total Mix)

Solve for X = 140
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Let:
x = grams of food X
y = grams of food Y
Step 1: Form equations

Total mixture:
x+y=300

Protein equation:
0.10x+0.15y=38

Step 2: Substitute
y=300−x
0.10x+0.15(300−x)=38
0.10x+45−0.15x=38
−0.05x+45=38
−0.05x=−7
x=0.05/7=140

Final Answer:
(E) 140 grams
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Let:
x = grams of food X
y = grams of food Y
Step 1: Form equations

Total mixture:
x+y=300

Protein equation:
0.10x+0.15y=38

Step 2: Substitute
y=300−x
0.10x+0.15(300−x)=38
0.10x+45−0.15x=38
−0.05x+45=38
−0.05x=−7
x=0.05/7=140

Final Answer:
(E) 140 grams
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