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BDSunDevil
statement 2 gives us 2 possibilities: 234 or 123 [different positive numbers arranged in ascending order] Not sufficient

together: since K*L*M is multiple of 6, 123 is the only possibilities.
C

I don't think this is correct.

The only 3 consecutive positive integer combination under 5 could be 1,2,3 or 2,3,4.

Statement 1 also gives you the same 2 possibilities. K*L*M could be 1*2*3 = 6 a multiple of 6.

2*3*4 = 24 (also a multiple of 6). NOT SUFFICIENT.

Statement 2 is saying that it has 2 different primes and 2,3 are in both, so again, statement 2 is NOT SUFFICIENT.

1) & 2) combined don't help as both still give you either 1,2,3 or 2,3,4 and the means will be different depending on which 3 numbers k,l,m are.

OA should be E.
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I think that the correct answer is C as the number "1" is not a prime number.

The prime number series starts from 2 ie: 2,3,5,7,11....... !
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prashantshukla
I think that the correct answer is C as the number "1" is not a prime number.

The prime number series starts from 2 ie: 2,3,5,7,11....... !

No, the correct answer is E. Consider below examples:

K=1, L=2=prime, M=3=prime.
K=2=prime, L=3=prime, M=4.
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prashantshukla
I think that the correct answer is C as the number "1" is not a prime number.

The prime number series starts from 2 ie: 2,3,5,7,11....... !

No, the correct answer is E. Consider below examples:

K=1, L=2=prime, M=3=prime.
K=2=prime, L=3=prime, M=4.

K=3,L=4,M=5
IS THIS SET POSSIBLE.BECAUSE THE CONDITION GIVEN IS "ELEMENTS OF THE SET ARE IN ASCENDING ORDER"
MAKING 2 ELEMENTS EQUAL WILL NOT VIOLATE THE CONDITION
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Bunuel
prashantshukla
I think that the correct answer is C as the number "1" is not a prime number.

The prime number series starts from 2 ie: 2,3,5,7,11....... !

No, the correct answer is E. Consider below examples:

K=1, L=2=prime, M=3=prime.
K=2=prime, L=3=prime, M=4.

K=3,L=4,M=5
IS THIS SET POSSIBLE.BECAUSE THE CONDITION GIVEN IS "ELEMENTS OF THE SET ARE IN ASCENDING ORDER"
MAKING 2 ELEMENTS EQUAL WILL NOT VIOLATE THE CONDITION

Given set is K, L, M, 5, 7. We are told that the set consists of different positive numbers arranged in ascending order.

Thus, set {K=3, L=4, M=5, 5, 7} is not possible because there are two 5's there.

P.S. Please turn of caps lock when posting.
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enigma123
Set X consists of different positive numbers arranged in ascending order: K, L, M, 5, 7. If K, L and M are consecutive integers, what is the arithmetic mean of set X?

(1) The product K × L × M is a multiple of 6
(2) There are at least 2 prime numbers among K, L and M


Good question:

Question stem: Numbers are different and arranged in ascending order so the range for K L M is 1 to 4.

Statement 1:
The product of 3 consecutive integers is always divisible by 6. Hence no new information.
the numbers can be 1,2,3 or 2,3,4
Not sufficient

Statement 2:
This is a trap as we might just think of 2,3,4 as 2 and 3 are the prime numbers. But even 1,2,3 has two primes. So this statement doesn't provide us anything new. Hence insufficient.

Combined:
Both the statements point to two cases so not sufficient.

Hence E.
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