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1) insufficient
2) ND+NC/CN gives a remainder of 5.

ND + NC / CN = (D+C)/C

So we know that (D+C)/C gives a remainder of 5.

The idea here is that if you add any multiple of C to C then you will definitely get a multiple of C. For eg. 4 is a multiple of 2. So (4+2)/2 will give R=0.
In this case though we have a number added to C leaving a remainder of 5. This means that D is not divisible by C and that D must leave a remainder of 5. Eg. (5+0)/10 leaves a remainder of 5 . (5+10)/10 will leave a remainder of 5 also. So the remainder will always be in D in the equation (D+C). This means that D/C will also give us a remainder of 5. Sufficient.
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Well, I am confused here and need some help.

I chose D.

Reason is as follows:
For statement A:
take D+1=12 and C+1=7 so 12/7 => remainder 5
if we take 11/6 => remainder is still 5

In the explanation above for D=CK + (K + 4), for different values of K, we are actually changing the value of D while keeping the value of C same. If the algebra calculations are correct and logic is correct, there must be some example to support this explanation.

We all agree to sufficiency of statement B.

Please advise.
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VeritasPrepKarishma
kingb
If N, C, and D are positive integers, what is the remainder when D is divided by C?

1) If D+1 is divided by C+1, the remainder is 5.
2) If ND+NC is divided by CN, the remainder is 5.

Stmnt 1: If D+1 is divided by C+1, the remainder is 5.

D+1 = (C+1)k + 5
D = Ck + (k + 4)
When D is divided by C, the remainder will vary with k.
If k = 0, remainder will be 4 (C is greater than 4)
If k = 1, remainder will be 5 (C is greater than 5)
If k = 2, remainder will be 6 (C is greater than 6)
etc

2) If ND+NC is divided by CN, the remainder is 5.
ND + NC = CN*k + 5
DN = CN*(k-1) + 5
D = C*(k-1) + 5/N
Now, N is a positive integer and remainder must be a positive integer too. The only value that N can take such that 5/N is a positive integer is 1. So N must be 1.
D = C*(k -1) + 5
When D is divided by C, remainder is 5.

Answer (B)

Sorry to bother , I just want to ask ... N can't be 5 ? 5/N will still be integer i.e. 1
Could you please explain why only value N can take is 1?
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anupamadw
VeritasPrepKarishma
kingb
If N, C, and D are positive integers, what is the remainder when D is divided by C?

1) If D+1 is divided by C+1, the remainder is 5.
2) If ND+NC is divided by CN, the remainder is 5.

Stmnt 1: If D+1 is divided by C+1, the remainder is 5.

D+1 = (C+1)k + 5
D = Ck + (k + 4)
When D is divided by C, the remainder will vary with k.
If k = 0, remainder will be 4 (C is greater than 4)
If k = 1, remainder will be 5 (C is greater than 5)
If k = 2, remainder will be 6 (C is greater than 6)
etc

2) If ND+NC is divided by CN, the remainder is 5.
ND + NC = CN*k + 5
DN = CN*(k-1) + 5
D = C*(k-1) + 5/N
Now, N is a positive integer and remainder must be a positive integer too. The only value that N can take such that 5/N is a positive integer is 1. So N must be 1.
D = C*(k -1) + 5
When D is divided by C, remainder is 5.

Answer (B)

Sorry to bother , I just want to ask ... N can't be 5 ? 5/N will still be integer i.e. 1
Could you please explain why only value N can take is 1?

Actually it can take value 5 too. I will rewrite the solution given above soon.
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nnitingarg
Well, I am confused here and need some help.

I chose D.

Reason is as follows:
For statement A:
take D+1=12 and C+1=7 so 12/7 => remainder 5
if we take 11/6 => remainder is still 5

In the explanation above for D=CK + (K + 4), for different values of K, we are actually changing the value of D while keeping the value of C same. If the algebra calculations are correct and logic is correct, there must be some example to support this explanation.

We all agree to sufficiency of statement B.

Please advise.

In statement 1, say if C+1 = 8 and D+1 = 21, remainder is 5.
C = 7 and D = 20, remainder is 6.
Not sufficient alone.
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1) is clearly insufficient

2) (ND+NC)/CN = Q + 5

==> (D/C)+1 = Q + 5
(D/C) = Q + 4

Hence Sufficient . Is the above approach correct ? Don't quite understand the Solutions given above.
Many Thanks
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bhatiavai
1) is clearly insufficient

2) (ND+NC)/CN = Q + 5

==> (D/C)+1 = Q + 5
(D/C) = Q + 4

Hence Sufficient . Is the above approach correct ? Don't quite understand the Solutions given above.
Many Thanks

No, it is not.

Take some simple numbers: 11 divided by 5 gives quotient as 2 and remainder as 1.

\(\frac{11}{5} \neq 2 + 1\)

So \(\frac{(ND+NC)}{CN} \neq Q + 5\)

Actually, ND + NC = Q*CN + 5
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1- Statement 1 insuf, C and D could be lot of number possibilities
2- N(D+C)/CN = D+C/C = D/C +1 = Q + 5/C => D = QC +4 is this good ?
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jimwild
1- Statement 1 insuf, C and D could be lot of number possibilities
2- N(D+C)/CN = D+C/C = D/C +1 = Q + 5/C => D = QC +4 is this good ?


I don't understand how you got Q + 5/C from Q*CN + 5.
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OA is definitely wrong. Should be E.
you cannot write remainder(ND/NC) = remainder(D/C)

eg remainder(20/15) = 5, remainder(4/3) = 1
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lifetantrik
OA is definitely wrong. Should be E.
you cannot write remainder(ND/NC) = remainder(D/C)

eg remainder(20/15) = 5, remainder(4/3) = 1

I agree. Let me expand this out to show the actual cases that prove insufficiency.

(1)
case 1: D = 19, C = 14. Obeys the statement, because when 20 is divided by 15, the remainder is 5. The answer to the question is also 5.
case 2: D = 28, C = 5. Obeys, the statement, because when 29 is divided by 6, the remainder is 5. The answer to the question, though, is 3. That's because when you divide 28 by 5, the remainder is 3.

(2)
case 1: D = 4, C = 3, N = 5. Obeys the statement, because when 20 + 15 is divided by 15, the remainder is 5. The answer to the question is 1.
case 2: D = 20, C = 15, N = 1. Obeys the statement, because when 20+15 is divided by 15, the remainder is 5. The answer to the question, however, is 5.

We have two different possible answers to the question for statement 1, and two different possible answers for statement 2. Now let's put them together.

(1+2)
case 1: D = 19, C = 14, N = 1.
- Obeys statement 1 (we already tested it).
- It also obeys statement 2, because when 19 + 14 is divided by 14, the remainder is 5.
- The answer to the question is 5.

case 2: D = 25, C = 6, N = 5.
- Obeys statement 1: 26 divided by 7 has a remainder of 5.
- Obeys statement 2: 125 divided by 30 has a remainder of 5.
- The answer to the question is 1.

So, the answer is (E).

That said, on the test, I would work on this one for about 90 seconds and then guess either C or E.
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N,C,D are positive integers.
d/c =quotient + rem. We need to find remainder.

1) D+1/C +1 = 0 + 5
--> D = 9, C = 2. 7+1/3 = 0+ 5. D/C =9/2 = remainder = 1
--> D = 10+1, C = 5+1 --> 11/6 = 0 +5 = D/C = 10/ 2 --> no remainder

So NS

2) (ND + NC)/ NC = q + 5 --> ND +1 = q + 5 -->ND = 4. what is D and N?

1) 2) --> still no value to C,D,N. So E
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ccooley
lifetantrik
OA is definitely wrong. Should be E.
you cannot write remainder(ND/NC) = remainder(D/C)

eg remainder(20/15) = 5, remainder(4/3) = 1

I agree. Let me expand this out to show the actual cases that prove insufficiency.

(1)
case 1: D = 19, C = 14. Obeys the statement, because when 20 is divided by 15, the remainder is 5. The answer to the question is also 5.
case 2: D = 28, C = 5. Obeys, the statement, because when 29 is divided by 6, the remainder is 5. The answer to the question, though, is 3. That's because when you divide 28 by 5, the remainder is 3.

(2)
case 1: D = 4, C = 3, N = 5. Obeys the statement, because when 20 + 15 is divided by 15, the remainder is 5. The answer to the question is 1.
case 2: D = 20, C = 15, N = 1. Obeys the statement, because when 20+15 is divided by 15, the remainder is 5. The answer to the question, however, is 5.

We have two different possible answers to the question for statement 1, and two different possible answers for statement 2. Now let's put them together.

(1+2)
case 1: D = 19, C = 14, N = 1.
- Obeys statement 1 (we already tested it).
- It also obeys statement 2, because when 19 + 14 is divided by 14, the remainder is 5.
- The answer to the question is 5.

case 2: D = 25, C = 6, N = 5.
- Obeys statement 1: 26 divided by 7 has a remainder of 5.
- Obeys statement 2: 125 divided by 30 has a remainder of 5.
- The answer to the question is 1.

So, the answer is (E).

That said, on the test, I would work on this one for about 90 seconds and then guess either C or E.

Hi

I believe that even without plugging numbers we can identify two equations from given statements using simply Dividend (N) = Divisor (D) * Quotient (Q) + Remainder (R)

St 1 - (C+1)x + 5 ;
St 2 - (CN)x + 5

Since there is no information about C nor N despite combination, the variables may or may not generate common values to consider, thus making insufficient to answer.
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