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himanshuhpr
Joined: 29 Aug 2012
Last visit: 28 Nov 2014
Posts: 24
Given Kudos: 56
Schools: Babson '14
GMAT Date: 02-28-2013
Updated on: 29 Oct 2014, 08:10
Originally posted by himanshuhpr on 19 Nov 2012, 14:33.
Last edited by Bunuel on 29 Oct 2014, 08:10, edited 1 time in total.
Last edited by Bunuel on 29 Oct 2014, 08:10, edited 1 time in total.
Renamed the topic and edited the question.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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53% (02:31) correct
47%
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Four spheres and three cubes are arranged in a line according to increasing volume, with no two solids of the same type adjacent to each other. The ratio of the volume of one solid to that of the next largest is constant. If the radius of the smallest sphere is ¼ that of the largest sphere, what is the radius of the smallest sphere?
(1) The volume of the smallest cube is 72pi.
(2) The volume of the second largest sphere is 576pi.
(1) The volume of the smallest cube is 72pi.
(2) The volume of the second largest sphere is 576pi.
19 Nov 2012, 17:01
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himanshuhpr
I'm happy to help with this.
From the prompt, we know the shapes are arranged in order of increasing volume, and the shapes are in the order:
1) sphere
2) cube
3) sphere
4) cube
5) sphere
6) cube
7) sphere
The ratios of the volumes are constant, so what we have is a geometric sequence. Call that ratio r. Let's say the volume of #1 is V. Then, the volumes are
1) sphere = V
2) cube = r*V
3) sphere = (r^2)*V
4) cube = (r^3)*V
5) sphere = (r^4)*V
6) cube = (r^5)*V
7) sphere = (r^6)*V
Then, the prompt tells us that radius of #1 is 1/4 the radius of #7. If the lengths from #1 to #7 increase by 4 times (scale factor = 4), then the volume increases by 4^3 = 64. For more on scale factors, see:
https://magoosh.com/gmat/2012/scale-fact ... decreases/
In other words, (r^6)*V = 64V ----> r^6 = 64 -----> r = 2
As it happens, we were easily able to solve for the numerical value of r here. Even if that were not the case, even if r were some ugly decimal, it would be the same. At this point, we know all the ratios, and all we need is a single value, any value on the list, and that would allow us to calculate every number on the list. In other words, any value would allow us to solve for V and, since we already know r, knowing V would allow us to calculate every term.
Now, that statements:
1. Vol. of smallest cube is 72 pi .
2. Vol. of second largest sphere is 576 pi.
Each statement gives us the numerical value of the volume of a specific shape in the arrangement, so each statement, all alone and by itself, will be sufficient for determining the answer to the prompt question.
That's why the OA is D
Does all this make sense?
Mike
20 Jul 2016, 10:04
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himanshuhpr
Answer: Option D
Please check the solution as attached
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