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On further simplification of the problem we get , x^(8y) - x^(8/y)

St 1 gives a unkown variable. Not Sufficient.
St 2 solves the unknown. Sufficient.

Answer: B
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Bunuel
What is the value of x^4y^2 - x^4/y^2 ?

(1) x = 2y

(2) y = 1


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Statement 1:
after substituting 2y for x, we are still left with y
Insufficient

Statement 2:
when y=1, the expression equates to 0
Sufficient

Answer: B
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FightToSurvive
On further simplification of the problem we get , x^(8y) - x^(8/y)

St 1 gives a unkown variable. Not Sufficient.
St 2 solves the unknown. Sufficient.

Answer: B

hi,
you will have to check on the equation you get after simplifying...
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X^4Y^2-x^4/Y^2

1. X=2Y; substituting values equation will be in one variable 2Y^4Y^2-2Y^4/Y^2, but value of y is still unknown, not sufficient

2. y=1, X^4-X^4=0; sufficient

Hence answer is B

Thanks,
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Bunuel
What is the value of x^4y^2 - x^4/y^2 ?

(1) x = 2y

(2) y = 1


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MAGOOSH OFFICIAL SOLUTION:
Attachment:
evaluationwexpo_explanation.png
evaluationwexpo_explanation.png [ 34.72 KiB | Viewed 4497 times ]
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Bunuel
What is the value of x^4y^2 - x^4/y^2 ?

(1) x = 2y

(2) y = 1
\(?\,\,\,\, = \,\,\,\,{x^4}{y^2} - {{{x^4}} \over {{y^2}}}\,\,\,\, = \,\,\,\,{x^4}\left( {{y^2} - {1 \over {{y^2}}}} \right)\)

\(\left( 1 \right)\,\,x = 2y\,\,\,\,\left\{ \matrix{\\
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {2,1} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,? = \,\,\,{2^{\,4}}\left( {1 - 1} \right) = 0 \hfill \cr \\
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {4,2} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,? = \,\,\,{4^{\,4}}\left( {4 - {1 \over 4}} \right) \ne 0\,\, \hfill \cr} \right.\)

\(\left( 2 \right)\,\,y = 1\,\,\,\,\, \Rightarrow \,\,\,\,\,\,?\,\, = \,\,{x^4} \cdot \left( {1 - {1 \over 1}} \right)\,\, = \,\,0\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{\rm{SUFF}}.\,\,\,\,\,\,\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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