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08 May 2015, 08:36
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B
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Difficulty:
55%
(hard)
Question Stats:
64% (02:23) correct
36%
(02:36)
wrong
based on 192
sessions
History
Date
Time
Result
Not Attempted Yet
If r = q^2 and r does not equal 0, is r > q?
(1) -rq/2 < 1
(2) 1/r < 1/q
(1) -rq/2 < 1
(2) 1/r < 1/q
08 May 2015, 10:13
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r would be greater than q for all the numbers except
-1<=q<0 and 0<q<=1
1) this does not give us any information about the value of q. try some numbers
2) 1/r < 1/q
this condition is true for all numbers except
-1<=q<0 and 0<q<=1
try 1 and 1/2 or 1/3
So, this gives us that r is out of this range and will always be greater than q.
Sufficient
B
-1<=q<0 and 0<q<=1
1) this does not give us any information about the value of q. try some numbers
2) 1/r < 1/q
this condition is true for all numbers except
-1<=q<0 and 0<q<=1
try 1 and 1/2 or 1/3
So, this gives us that r is out of this range and will always be greater than q.
Sufficient
B
akhilbajaj
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Concentration: Entrepreneurship, Sustainability
Schools: IIMB IIMB EPGP"18 Insead Sept '17 ISB '18
GMAT 1: 650 Q45 V34
GMAT 2: 740 Q51 V39
GRE 1: Q790 V650
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Schools: IIMB IIMB EPGP"18 Insead Sept '17 ISB '18
GMAT 2: 740 Q51 V39
GRE 1: Q790 V650
Posts: 54
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09 May 2015, 01:23
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The question asks if r>q or \(q^2 > q\).
This is true if q>1, q<0
St1- rearrange to get rq>-2
Option 1- rq<0, => q<0, r>0>q (since\(r = q^2\) which cannot be negative)
Option 2- rq>0, we cannot determine if r>q.
Insufficient
St2- 1/r < 1/q
This is only possible when q>0 (since \(r = q^2\) which cannot be negative).
=> r>q
Sufficient.
Answer B
This is true if q>1, q<0
St1- rearrange to get rq>-2
Option 1- rq<0, => q<0, r>0>q (since\(r = q^2\) which cannot be negative)
Option 2- rq>0, we cannot determine if r>q.
Insufficient
St2- 1/r < 1/q
This is only possible when q>0 (since \(r = q^2\) which cannot be negative).
=> r>q
Sufficient.
Answer B
