Ekland
Is x < - 20 ?
(1) x^2 + 40x + 391 = 0
(2) x^2 = 529
Statement 2:
Since \(20^2=400\) and \(30^2 = 900\), the positive root must be between 20 and 30.
For the units of \(x^2\) to be 9, x must have a units digit of 3 or 7.
Since 529 is much closer to 400 than to 900, the positive root must be 23, implying that the negative root is -23.
If x=23, the answer to the question stem is NO.
If x=-23, the answer to the question stem is YES.
INSUFFICIENT.
RULE:
For any DS problem, there must be at least one case that satisfies BOTH statements.
Statement 1:
\(x^2 + 40x + 391 = (x+a)(x+b)\), where \(a+b = 40\).
In accordance with the rule above, one of the roots of this quadratic must be 23 or -23.
Thus, the two factors must look as follows:
\((x+23)(x+b)\)
Since 23+b = 40, b=17, with the result that the second factor is (x+17):
\((x+23)(x+17)\)
Thus, x=-23 or x=-17.
If x=-17, the answer to the question stem is NO.
If x=-23, the answer to the question stem is YES.
INSUFFICIENT.
Statements combined:
Only x=-23 satisfies both statements.
Thus, the answer to the question stem is YES.
SUFFICIENT.