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shasadou
On a fishing expedition, a group of 13 fishermen caught a total of 160 fish. \ Did any one fisherman catch more than 15 fish?

(1) The fisherman who caught the third-most fish caught 11 fish.

(2) The fisherman who caught the second-most fish caught 12 fish

Hi,
for 160 fish, the average catch is 160/13 that is 11 and half approx..

lets see the statements..
1) The fisherman who caught the third-most fish caught 11 fish.
for making the higher most catches the lowest posible, let everyone from thirdmost to lowest caught equal number of fishes, 11..
so the two topmost will catch= 160-11*11=39
39 will be caught by 2, which means atleast 1 caught>19
Suff

(2) The fisherman who caught the second-most fish caught 12 fish
same as (1), let all from second most to lowest catch equal number of fishes= 12*12=144
so the highest will catch 160-144=16 >15
Suff

D


Hi Chethan,

Thanks for the solution, but 160/13 is 12.3 , so we can approximate to 12 as average or any other reason to take 11 as avg ?

Please share your answer for the stat 1 and stat 2 considering 12 as avg.
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Hi Chetan,
Can you please make me understand that how using Statement 1 how can we say say for sure that 39 fish will be caught by 2 different men. There can be a case where one catches 30 and other catches 9. In the question stem there's no such information :cry:

In statement 2 it tells that 2nd most guy caught 12 so now we can conclusively say that the only remaining guy caught >15. Please help me understand :(
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shasadou
On a fishing expedition, a group of 13 fishermen caught a total of 160 fish. \ Did any one fisherman catch more than 15 fish?

(1) The fisherman who caught the third-most fish caught 11 fish.

(2) The fisherman who caught the second-most fish caught 12 fish


(1) The fisherman who caught the third-most fish caught 11 fish.

total fishermen = 13
since 11 is the third most , we need to minimise the first two
let first two be a and b
to minimise a and b
let all remaining 11 fishermen catch 11 fishes
fishes remaining for a and b = 160-(11*11)=39
now 39 can be divided as 27,12 this gives us minimum b and max a
or, 20,19, which gives us maximum b minimum a
thus the highest , a >12
sufficient

(2) The fisherman who caught the second-most fish caught 12 fish

again to minimise a
let all fishermen catch 12 fishes
therefore a = 160-(12*12) = 160-144=16
therefore sufficient

D
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atreyaraja
Hi Chetan,
Can you please make me understand that how using Statement 1 how can we say say for sure that 39 fish will be caught by 2 different men. There can be a case where one catches 30 and other catches 9. In the question stem there's no such information :cry:

In statement 2 it tells that 2nd most guy caught 12 so now we can conclusively say that the only remaining guy caught >15. Please help me understand :(

The question asks Did any one fisherman catch more than 15 fish?
Statement 1 : if 2 fishermans catch total of minimum 39 fishes, then at least one of them will catch more than 15 fishes;
e.g 1,38 2,37 ..... 19,20, .... 38,1.
Sufficient


I hope it's clear to you now.
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VeritasPrepKarishma
shasadou
On a fishing expedition, a group of 13 fishermen caught a total of 160 fish. \ Did any one fisherman catch more than 15 fish?

(1) The fisherman who caught the third-most fish caught 11 fish.

(2) The fisherman who caught the second-most fish caught 12 fish


There were 13 fishermen and a total of 160 fish. One thing that immediately comes to mind is that many fishermen could have easily caught no fish. So it is certainly possible with either statement that the fisherman who caught maximum number of fish caught, say 100 fish. So more than 15 is certainly possible. What we now need to figure out is whether 15 or less for the fisherman who caught the most is also possible.

(1) The fisherman who caught the third-most fish caught 11 fish.

We need to find the case in which the fisherman with most fish caught 15 or less. So other fishermen need to catch as many as they can.
Arranging in ascending order of number of fish caught: 10, 10, 10, .... 10, 11, 14, 15
This adds up to only 140 fish. So the fisherman with most fish MUST HAVE caught more than 15 fish.
Sufficient.

(2) The fisherman who caught the second-most fish caught 12 fish.

Again, we need to find the case in which the fisherman with most fish caught 15 or less. So other fishermen need to catch as many as they can.
Arranging in ascending order of number of fish caught: 11, 11, 11, .... 11, 11, 12, 15
This adds up to only 148 fish. So the fisherman with most fish MUST HAVE caught more than 15 fish.
Sufficient.

Answer (D)


Hi Karishma,

Any particular reason for deserting the following case:
1,1,1,1,1,1,1,1,1,1,12,X,X?

Regards,
Ravi
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VeritasPrepKarishma
shasadou
On a fishing expedition, a group of 13 fishermen caught a total of 160 fish. \ Did any one fisherman catch more than 15 fish?

(1) The fisherman who caught the third-most fish caught 11 fish.

(2) The fisherman who caught the second-most fish caught 12 fish


There were 13 fishermen and a total of 160 fish. One thing that immediately comes to mind is that many fishermen could have easily caught no fish. So it is certainly possible with either statement that the fisherman who caught maximum number of fish caught, say 100 fish. So more than 15 is certainly possible. What we now need to figure out is whether 15 or less for the fisherman who caught the most is also possible.

(1) The fisherman who caught the third-most fish caught 11 fish.

We need to find the case in which the fisherman with most fish caught 15 or less. So other fishermen need to catch as many as they can.
Arranging in ascending order of number of fish caught: 10, 10, 10, .... 10, 11, 14, 15
This adds up to only 140 fish. So the fisherman with most fish MUST HAVE caught more than 15 fish.
Sufficient.

(2) The fisherman who caught the second-most fish caught 12 fish.

Again, we need to find the case in which the fisherman with most fish caught 15 or less. So other fishermen need to catch as many as they can.
Arranging in ascending order of number of fish caught: 11, 11, 11, .... 11, 11, 12, 15
This adds up to only 148 fish. So the fisherman with most fish MUST HAVE caught more than 15 fish.
Sufficient.

Answer (D)


Hi Karishma,

Any particular reason for deserting the following case:
1,1,1,1,1,1,1,1,1,1,12,X,X?

Regards,
Ravi

For which statement are you suggesting this case?

Stmnt 1: Here it will be 1,1,1,1,1,1,1,1,1,1,11,X,Y

Stmnt 2: Here it will be 1,1,1,1,1,1,1,1,1,1,1,12,Y

In both these cases, Y will certainly be more than 15 to get the sum up to 160.
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VeritasPrepKarishma
shasadou
On a fishing expedition, a group of 13 fishermen caught a total of 160 fish. \ Did any one fisherman catch more than 15 fish?

(1) The fisherman who caught the third-most fish caught 11 fish.

(2) The fisherman who caught the second-most fish caught 12 fish


There were 13 fishermen and a total of 160 fish. One thing that immediately comes to mind is that many fishermen could have easily caught no fish. So it is certainly possible with either statement that the fisherman who caught maximum number of fish caught, say 100 fish. So more than 15 is certainly possible. What we now need to figure out is whether 15 or less for the fisherman who caught the most is also possible.

(1) The fisherman who caught the third-most fish caught 11 fish.

We need to find the case in which the fisherman with most fish caught 15 or less. So other fishermen need to catch as many as they can.
Arranging in ascending order of number of fish caught: 10, 10, 10, .... 10, 11, 14, 15
This adds up to only 140 fish. So the fisherman with most fish MUST HAVE caught more than 15 fish.
Sufficient.

(2) The fisherman who caught the second-most fish caught 12 fish.

Again, we need to find the case in which the fisherman with most fish caught 15 or less. So other fishermen need to catch as many as they can.
Arranging in ascending order of number of fish caught: 11, 11, 11, .... 11, 11, 12, 15
This adds up to only 148 fish. So the fisherman with most fish MUST HAVE caught more than 15 fish.
Sufficient.

Answer (D)


For statement 1. The fisherman who caught the third-most fish caught 11 fish
Instead of 10, 10, 10, .... 10, 11, 14, 15
can it be 11,11,11, ... 11,11,14,15 , here there are 11 fishermen who caught 3rd-most highest fish
still it is less than 160 , but is it the better way?

thanks
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Statement 1)

if the third most caught 11 lets just assume fishermen 1-11 caught 11 (to maximize this value)=121
That means fishermen 12 and 13 caught 139 between the two of them. If fisherman 12 caught 14 (maximize this value) then fisherman 13 caught 25. To see if a fisherman caught more than 15 we need to maximize the other values

Statemen 2)
Same approach of maximizing all other values
We'll assume fishermen 1-12 caught 12 fish=144
160-144=16
suff

D
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chetan2u
shasadou
On a fishing expedition, a group of 13 fishermen caught a total of 160 fish. \ Did any one fisherman catch more than 15 fish?

(1) The fisherman who caught the third-most fish caught 11 fish.

(2) The fisherman who caught the second-most fish caught 12 fish

Hi,
for 160 fish, the average catch is 160/13 that is 11 and half approx..

lets see the statements..
1) The fisherman who caught the third-most fish caught 11 fish.
for making the higher most catches the lowest posible, let everyone from thirdmost to lowest caught equal number of fishes, 11..
so the two topmost will catch= 160-11*11=39
39 will be caught by 2, which means atleast 1 caught>19
Suff

(2) The fisherman who caught the second-most fish caught 12 fish
same as (1), let all from second most to lowest catch equal number of fishes= 12*12=144
so the highest will catch 160-144=16 >15
Suff

D

chetan2u,
Hello chetan2u, a prompt question regarding this question, it's more of a wording issue, when it says that The fisherman who caught the third-most fish caught 11 fish. doesn't that mean that the value of the 3rd will be unique? I was really puzzled on whether I should count everybody below the third person or i could include the third person so I didn't know if it should be 10*11 or 11*11, I see that you have included the 3rd person , so I was wondering was there another hint that guided you or it is the common mathematical approach?
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A group of fisherman caught a total of 160 fish. To determine if one fisherman caught more than 15 fish, we need to maximize the number of fish each fisherman caught.

(1) If the fishermen who caught the third most fight caught 11 fish, lets consider the following scenario:

_ _ _ _ _ _ _ _ _ _11_ _

To maximize the number of fish caught:

11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, _ _

The eleven fisherman caught 121 fish. Between the 12th and 13th fisherman, the two caught 39 fish. At least one fisherman caught more than 15 fish. SUFFICIENT.

(1) If the fishermen who caught the second most fight caught 12 fish, lets consider the following scenario:

_ _ _ _ _ _ _ _ _ _ _ 12 _

12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, _

The twelve fisherman caught 144 fish. The last fisherman must have caught at least 16 fish. SUFFICIENT.

Answer is D.
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KarishmaB TargetTestPrep in questions that give 'third most', for the vlues below that does gmat accept if we use the same values as the third most value or do the values below that value have to be less than third most value?
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KarishmaB TargetTestPrep in questions that give 'third most', for the vlues below that does gmat accept if we use the same values as the third most value or do the values below that value have to be less than third most value?

A GMAT question will clarify whether values are unique or could be same. Every "live" GMAT question goes through so much testing that any ambiguity is weeded out.
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It seems everyone is ignoring the following possibility, in both statements we are talking about the "fisherman who caught the third-most fish", and everyone assumed something like this:
"for making the higher most catches the lowest possible, let everyone from third most to lowest caught equal number of fishes", but...

1) "The fisherman who caught the third-most fish caught 11 fish" could mean the third largest amount of fish, he could be the fisherman with the least fish caught, if there were just 3 distinct amounts. So let's assume that one fisherman caught six, one fisherman caught 11 (3rd largest amount), ten fisherman caught 12, one caught 13. It's easily shown how this logic is applicable to statement 2 as well and in each case can yield both >15 or not. Therefore in my opinion ->E, or just a very poorly phrased question.
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It seems everyone is ignoring the following possibility, in both statements we are talking about the "fisherman who caught the third-most fish", and everyone assumed something like this:
"for making the higher most catches the lowest possible, let everyone from third most to lowest caught equal number of fishes", but...

1) "The fisherman who caught the third-most fish caught 11 fish" could mean the third largest amount of fish, he could be the fisherman with the least fish caught, if there were just 3 distinct amounts. So let's assume that one fisherman caught six, one fisherman caught 11 (3rd largest amount), ten fisherman caught 12, one caught 13. It's easily shown how this logic is applicable to statement 2 as well and in each case can yield both >15 or not. Therefore in my opinion ->E, or just a very poorly phrased question.

For either statement, write down a case in which everyone caught 15 or fewer fish but the total was 160 fish for the 13 fishermen.
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