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04 Apr 2016, 07:13
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If \(\frac{4t}{3x} = \frac{2}{3y} +\frac{2}{5y}\) and xy is not equal to 0, is t equal to 1?
(1) y = 5
(2) \(x = \frac{5y}{4}\)
(1) y = 5
(2) \(x = \frac{5y}{4}\)
04 Apr 2016, 17:15
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I simplified the equation to \(t = 4x / 5y\). Also note that neither x nor y will be 0.
1) Given \(y = 5\), when we substitute this value into the simplified equation we get \(t = 4x / 25\). When \(x = 25/4\) the answer will be yes, if x is any other value the answer will be no => INSUFFICIENT
2) Given \(x = 5y/4\), this value substituted into the simplified formula yields \(t = 1\), so the answer is yes => SUFFICIENT
Answer: B
1) Given \(y = 5\), when we substitute this value into the simplified equation we get \(t = 4x / 25\). When \(x = 25/4\) the answer will be yes, if x is any other value the answer will be no => INSUFFICIENT
2) Given \(x = 5y/4\), this value substituted into the simplified formula yields \(t = 1\), so the answer is yes => SUFFICIENT
Answer: B
22 Jul 2016, 11:07
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Bunuel
Hi Bunuel
I was wondering if we could take the LCM of 5y and 3y which i thought will be 15 y. with this approach we end up eliminating y from the equation and to know the value of t, we only need the value of x. However using this method i am getting the incorrect answer. Can you help me understand why exactly we cant do this ?
Regards,
Shradha
