A train traveled from station X to station Y at a constant speed of 88

Question

A train traveled from station X to station Y at a constant speed of 88 feet per second. Is the distance that the train traveled from station X to Station Y greater than 40 miles? (1 mile = 5,280 feet)

(1) It took less than 45 minutes for the train to travel from station X to Station Y.
(2) It took more than 42 minutes for the train to travel from station X to Station Y

Nightfury14 · Accepted Answer

Speed of train = 88feet/sec = (88x60)feet/min
=> (88x60x)/5280] mile/ min
=> 1mile/ min

Statement 1) It took less than 45min. Train could have reached after 39 min (travelling 39 miles) or after 41mins (travelling 41miles) .. Insufficient
Statement 2) It took more than 42min. The train travelled more than 42miles .. Sufficient

Choice B) alone is sufficient to ans the question.

Good luck
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ScottTargetTestPrep · Answer

We can let d = the distance between station X and station Y. We need to determine whether d > 40 miles.
Since the distance is given in miles but the speed, or rate, is given in feet per second, we need to convert the distance from miles to feet. Since 1 mile = 5,280 feet, 40 miles = 40 x 5,280 = 211,200 feet.

Since rate x time = distance and we have a rate of 88 ft/s, we can change the question to:

Is 88t > 211,200 feet?

Is t > 2,400 seconds?

Since 2,400 seconds = 2,400/60 = 40 minutes, the question becomes:

Is t > 40 minutes?

Statement One Alone:

It took less than 45 minutes for the train to travel from station X to Station Y.

Since less than 45 minutes could mean 42 minutes or 38 minutes, statement one does not tell us whether t > 40 minutes. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

It took more than 42 minutes for the train to travel from station X to Station Y.

Statement two tells us that t is greater than 40 minutes.

Answer: B

LogicGuru1 · Answer

speed of train = \frac{88feet}{sec}= \frac{60.0012 miles}{hour} = \frac{1mile}{minute}

(1) It took less than 45 minutes for the train to travel from station X to Station Y.
INSUFFICIENT:- If the Train took less than 45 minutes then it has covered less than 45 mile. But we cannot determine precisely how many miles. Less than 45 can be anything from 1 to 44. Train may reach in 30 minutes or 38 minutes or 44 minutes hence distance can be 30 miles, 38 miles or 44 miles. Anything less than 45 miles.
(2) It took more than 42 minutes for the train to travel from station X to Station Y
SUFFICIENT:- We can confidently answer "YES, The distance is more than 40 Miles"

ANSWER IS B

Divyadisha · Answer

Converting the speed to mile/hr:- 88*60*60/5280= 60 miles/hr (1) It took less than 45 minutes for the train to travel from station X to Station Y. distance = speed*time since time <45 minutes, distance will be <60*45/60, i.e. <45. But it may or may not be <40 miles. (2) It took more than 42 minutes for the train to travel from station X to Station Y distance> 60*42/60 i.e. >42. Sufficient. B is the answer

Mavs1205 · Answer

Quick question, how do you guys convert the mileage of the train so fast?

I wrote it out and the conversion alone took me forever. I'm obviously missing something...

88ft/1sec x 60sec/1min x 60min/1hr x 1mile/5280ft = 60

Any help or shortcuts? Thanks!

testcracker · Answer

just divide 5280 by 88, and you will get number of seconds the train needs to cover 1 mile. that's it...

hope this helps
cheers ...

akshayk · Answer

R = 88 feet per second => 60 miles per hour. D > 40 ? 1) t < 45 minutes t = 44 minutes. D > 40 miles (Yes) t = 20 minutes D < 40 miles (No) Insufficient. 2) t > 42 minutes t = 42.1 minutes D = \frac{42.1}{60} * 60 = 42.1 miles Sufficient. Answer is B.

Basshead · Answer

A train traveled from station X to station Y at a constant speed of 88 feet per second. Is the distance that the train traveled from station X to Station Y greater than 40 miles? (1 mile = 5,280 feet)

1 mile = 5,280 feet
We're told the train travels at a constant speed of 88 feet per second.

5,280 feet / 88 feet = 60 seconds per mile.

To determine if the distance that train traveled from Station X to Station Y is greater than 40 miles, we need to determine if the train traveled for  more than 40 minutes . If we can answer with certainty, the statement will be sufficient.

(1) It took less than 45 minutes for the train to travel from station X to Station Y.

Train could have traveled for 1 minute or 42 minutes. Not sufficient.

(2) It took more than 42 minutes for the train to travel from station X to Station Y

42 minutes = at least 42 miles. Sufficient.

Answer is B.

giovannisumano · Answer

is there a shortcut to answer this kind of questions? they always take me a LOT of time to answer.

hassan233 · Answer

The question gives you the speed in feet/second, but the statements give you time in  minutes  and the question asks you if the distance is over X  miles . The first thing I would do is convert the speed from feet/sec to miles/minute.
To do this, we would do 88ft/sec * 60 sec/min / 5280ft/mile = 1 mile/minute

Statement 1 tells us that the time was less than 45 minutes, which means the distance is less than 45 miles. Does that mean the distance is greater than 40? No. It could be 43 or 35.

Statement 2 tells us that the time was greater than 42 minutes, which means the distance is more than 42 miles. Does that mean the distance is greater than 40 miles? Yes. distance > 42 means the distance is also > 40.

sm1510 · Answer

question seen in GMAT Prep # 6

Bunuel · Answer

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Added the tag. Thank you.

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A train traveled from station X to station Y at a constant speed of 88

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