Bunuel
x + y = 8. Does x = 3?
(1) 2x + z = 8
(2) 3y − 4z = 7
Target question: Does x = 3 Given: x + y = 8 Statement 1: 2x + z = 8 No information about z.
So, statement 1 is NOT SUFFICIENT
NOTE: If we're not quite convinced that statement 1 is not sufficient, we might TEST some values.
Case a: x = 1, y = 7, and z = 6 (satisfies the given info AND statement 1). In this case
x = 1Case b: x = 0, y = 8, and z = 8 (satisfies the given info AND statement 1). In this case
x = 2Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: 3y − 4z = 7 Once again, we have no information about z.
So, statement 2 is NOT SUFFICIENT
ONCE AGAIN, if we're not quite convinced that statement 1 is not sufficient, we might TEST some values.
Case a: x = 7, y = 1, and z = 1 (satisfies the given info AND statement 2). In this case
x = 7Case b: x = 3, y = 5, and z = 2 (satisfies the given info AND statement 2). In this case
x = 3Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Given: x + y = 8, which means
y = 8 - xStatement 2: 3y − 4z = 7. Replace y with
8 - x to get: 3(
8 - x ) - 4z = 7
Simplify to get:
-3x - 4z = -17Statement 1: 2x + z = 8
Since we now have two equations with 2 variables (
-3x - 4z = -17 and 2x + z = 8), AND those 2 equations are not equivalents, we COULD solve this system for x, which means we COULD answer the
target question.
Since we COULD answer the
target question with certainty, the combined statements are SUFFICIENT
Answer = C