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Bunuel
If n is a positive integer with k digits, how many possibilities are there for the value of n?

(1) k = 1
(2) n < 10

IMO D

Given n is a positive integer with k digits.

From statement 1
k=1 which means n is a single digit positive integer
9 possible positive integer values of n exists (omitting 0 as 0 is neither positive nor negative)
Sufficient

From statement 2
n<10 means n is a single digit positive integer
9 possible positive integer values of n exists
Sufficient

Hence D
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Bunuel
If n is a positive integer with k digits, how many possibilities are there for the value of n?

(1) k = 1
(2) n < 10

1. if we have 1 digit, then n must be 1, 2, 3, 4, 5, 6, 7, 8, or 9. - 9 possibilities. sufficient.

2. n<10.
n can be 1,2,3,4,5,6,7,8, or 9. again 9 possibilities.

answer is D.
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Bunuel
If n is a positive integer with k digits, how many possibilities are there for the value of n?

(1) k = 1
(2) n < 10

Question : How many possibilities are there for the value of n?

Statement 1:: k=1
i.e. n is a single digit positive Integer
Since there are only 9 single digit positive Integers, Hence
SUFFICIENT

Statement 2:: n<10
i.e. n is a single digit positive Integer
Since there are only 9 single digit positive Integers, Hence
SUFFICIENT

Answer: option D
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