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Bunuel
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Hi all,
statement 1
If p=0, then k=3 -> so K prime! Am I missing something?
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Hi all,
statement 1
If p=0, then k=3 -> so K prime! Am I missing something?

Hi

Its given that p is a positive integer, so we cannot take the case where p=0.
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I thought zero is both positive and negative.
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Bunuel
If p is a positive integer, is integer k prime?

(1) 3p + 3 = k
(2) 7! + 3 = k

#1 k= 3(P+1), so k can't be prime as it's definitely divided by 3.

#2 k= 3(1+x), where x>0 and Integer, so again k can't be prime as it's definitely divided by 3..

D Each statement independently sufficient.



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rashwiniyer
I thought zero is both positive and negative.
rashwiniyer

zero is neither +ve nor -ve.



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Abhishek009
Bunuel
If p is a positive integer, is integer k prime?

(1) 3p + 3 = k
(2) 7! + 3 = k

FROM STATEMENT - I ( SUFFICIENT )

3p + 3 = k

Or, 3 ( p + 1 ) = k

So, k is divisible by 3 ; hence k can not be a prime number...


FROM STATEMENT - II ( SUFFICIENT )

7! + 3 = k

Or, 7*6*5*4*3*2*1 + 3 = k

Or, 3 ( 7*6*5*4*2*1 + 1 ) = k

So, k is divisible by 3 ; hence k can not be a prime number...

Thus, EACH statement ALONE is sufficient to answer the question asked, aswer will be (D)

For statement 1, stating that if it is divisible by 3, then it is not prime I believe it is wrong: 3 is prime and is divisible by 3. The correct statement would be that for every value of x, the result won't be prime.
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