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25 Jan 2018, 23:54
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
51% (02:11) correct
49%
(02:02)
wrong
based on 297
sessions
History
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Not Attempted Yet
If the average (arithmetic mean) annual income for a group of people is x, where x >0, and the annual income of one of the members of the group, Joe, increases by 25%, by what percent does the average income of the whole group increase?
(1) There are 8 people in the group.
(2) The total initial income of the group is 9 times Joe's initial income.
(1) There are 8 people in the group.
(2) The total initial income of the group is 9 times Joe's initial income.
26 Jan 2018, 00:12
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IMO B
1) Initial total income = 8x, New total = 8x - Joe's previous income + Joe's new income. No idea about what was Joe's previous income or even how it was related with group's income to estimate the change in total income, therefore Not Sufficient.
2) Joe's initial income = a, Group's initial income=9a, total income=10a
Joe's new income = 1.25a, Group's new income = 9+1.25a=10.25a
Therefore % change in average=% change in total income= 2.5%, Sufficient.
1) Initial total income = 8x, New total = 8x - Joe's previous income + Joe's new income. No idea about what was Joe's previous income or even how it was related with group's income to estimate the change in total income, therefore Not Sufficient.
2) Joe's initial income = a, Group's initial income=9a, total income=10a
Joe's new income = 1.25a, Group's new income = 9+1.25a=10.25a
Therefore % change in average=% change in total income= 2.5%, Sufficient.
26 Jan 2018, 00:45
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urvashis09
Hi
I also think the answer is B. Similar logic as yours. But in second statement, I think total income will be 9a only, and not 10a. After increase in Joe's income, group's total income will be = 9.25a. % increase = 0.25/9 * 100.
