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Can somebody explain how statement 2 is also sufficient? I thought the answer should be A.

Hi,

Radius of each can=4.5 cm therefore dia=9 cms.
Now, see that the rectangular box has base area as 90 cm X 45 cm therefore i can put(along its breadth i.e. 45 cms) 5 cans and i can put (along its length i.e. 90 cms) 10 cans.

So the number of cans at the base will be 10 X 5= 50 cans.

Now, we need to keep 200 cans.

Therefore, at base we can keep=50 cans, we need=200/50=4 stacks to keep all the cans in the rectangular box.

Hence the Statement 2 is also sufficient.

I hope it was clear :)
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Ah okay I got it now, makes sense. Thanks for that :)
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