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13 Apr 2019, 03:07
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
59% (01:34) correct
41%
(01:56)
wrong
based on 227
sessions
History
Date
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Not Attempted Yet
Each of the 20 students has 9, or 10, or 11 books. What is the average number of the books that the students have?
(1) The number of the students who have 9 books is equal to the number of the students who have 11 books.
(2) The number of the students who have 9 books is greater than the number of the students who have 10 books.
(1) The number of the students who have 9 books is equal to the number of the students who have 11 books.
(2) The number of the students who have 9 books is greater than the number of the students who have 10 books.
vedavyas003
GMAT 1: 600 Q49 V25
Posts: 2
14 Apr 2019, 03:12
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Sanjeetgujrall
Having same number of students with 9 and 11 books so
average will be \(\frac {9 n + 10 k + 11 n} {(2n+k)}\)
we can represent this as
\(\frac{n ( 9 +11 ) + 10k}{2n + k }\) = \(\frac {n (20) + 10k}{ 2n+k}\) = \(\frac {2n(10) + 10k }{2n+k}\) = \(\frac {(2n + k)10 }{2n+k}\) = 10
hope this is helpful.
General Discussion
13 Apr 2019, 05:24
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Can someone explain how is it A? I think its E
Let students with 9 books =x, 10 books=y and 11 books=z
We can x=7,y=6,z=7 or x=8,y=4,z=8. Average will be different
The above example will give different average for C as well...
Let students with 9 books =x, 10 books=y and 11 books=z
We can x=7,y=6,z=7 or x=8,y=4,z=8. Average will be different
The above example will give different average for C as well...
