If x and y are integers and xy = 6, what is the value of x?

Question

(1) x > y + 1
(2) x = 6y

Chetan's  questions

ShankSouljaBoi · Answer

Will go with C
1. x> 6/x + 1. Simplify !
--->  /x > 0 so the range is x is between -2 and 0 i.e. x = -1 or x = more than 3 i.e. x= 6 . Not sufficient

2. x^2 = 36 ----> x = 6 or -6 . Insufficient

Combining 1 and 2 ---> unique x is 6.

minustark · Answer

Since x and y are integers, they can take the values of (2,3),(6,1),(-2,-3),(-6,-1) for xy = 6.

Statement 1, x > y + 1. x can be either -1 or 6.  NOT SUFFICIENT.

Statement 2, x = 6y. x can be 6 or -6.  NOT SUFFICIENT.

Combining both statement, 6 is the single value that meets the requirements.  SUFFICIENT.

ANSWER IS C.

ManthanGala · Answer

I think its C.

1- (x,y) = (-1,-6) / (6,1)
2- (x,y) = (-6,-1) / (6,1)

Therefore x=6.

exc4libur · Answer

(x,y)=integers: xy=6, (x,y;y,x)=(2,3;-2,-3;6,1;-1,-6)

(1) x > y + 1   insufic 
(x,y)=(6,1;-1,-6); x=(6,-1)

(2) x = 6y   insufic 
(x,y)=(6,1;-6,-1); x=(6,-6)

(1&2)   sufic 
x=6

Ans (C)

KSBGC · Answer

Note : no sign specific.

xy = 6

1*6 = 6
2*3 = 6

the values could be negative too.

we are looking for the value of x.

Statement 1; x>y + 1

x - y > 1

It indicates that both x and y are positive.

but it's not possible to separate the value of x.

Statement 2;

x = 6y

Given ,

xy = 6

6y*y = 6

y^2 = 1

y = +1 or - 1.

Thus , NOT sufficient.

Combining both statements :

From statement 1, we know that both x and y are positive and from 2nd statement we know that y must be 1.

xy = 6

x(1) = 6

x = 6 .

C is the correct statement .

If x and y are integers and xy = 6, what is the value of x?

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