Bunuel
Set S contains five distinct positive integers, each of which is greater than 2. Is the mean of S greater than the median of S?
(1) The sum of the elements of S is equal to 20 times the smallest element of S.
(2) The median of S is 8 greater than the smallest element of S.
Assume smallest term of the set = \(a\)
(1) The sum of the elements of S is equal to 20 times the smallest element of S.
--> Sum = \(20a\) & Mean = \(\frac{20a}{5} = 4a\)
Case 1: Set = {\(3, 4, 5, 6, 42\)}; Sum = \(60\), Mean = \(4a = 12\), Median = \(5\) --> Mean > Median
Case 2: Set = {\(3, 12, 13, 15, 17\)}; Sum = \(60\), Mean = \(4a = 12\), Median = \(13\) --> Mean < Median
-->
Insufficient(2) The median of S is 8 greater than the smallest element of S
Case 1: Set = {\(a, a + 1, a + 8, a + 9, a + 12\)}, Mean = \(a + 6\), Median = \(a + 8\) --> Mean < Median
Case 2: Set = {\(a, a + 3, a + 8, a + 99, a + 100\)}, Mean = \(a + 42\), Median = \(a + 8\) --> Mean > Median
-->
InsufficientCombining (1) & (2),
Mean = \(4a\) & Median = \(a + 8\)
Question: Is Mean > Median ??
Is \(4a > a + 8\) ?
--> Is \(4a - a > 8\) ?
--> Is \(3a > 8\) ?
--> Is \(a > 2.66\) ?
--> Always True (Since all terms are greater than 2 and are integers, Possible values of \(a = 3, 4, 5, . . .\) ) -->
SufficientOption C