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Set S contains five distinct positive integers, each of which is greater than 2. Is the mean of S greater than the median of S?


(1) The sum of the elements of S is equal to 20 times the smallest element of S.

(2) The median of S is 8 greater than the smallest element of S.


Question: Is mean > median?

Let terms are a, b, c, d, e such that a<b<c<d<e

Statement 1: a+b+c+d+e = 20a

1, 2, 3, 4, 10 mean > Media
2, 5, 10, 11, 12 mean > Media

Mean is always greater than median hence

SUFFICIENT

Statement 2: c = 8+a

For smallest mean terms may be 1, 2, 9, 10, 11 Mean < Median

For Large mean terms may be 1, 2, 9, 100, 200 Mean > Median

NOT SUFFICIENT

Answer: Option A


GMATinsight
Least value cannot be taken as 1
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St. 1 -- Not sufficient. Sum of 5 terms is 20x (x being the smallest term greater than 2). Therefore, average is 4x. We can't possibly deduce any information about the median from this information. Median could be greater than 4x or less than 4x.

St. 2 -- Not sufficient. Median is 8 greater than the smallest term. We can't deduce anything about the mean from this information.

Merging the two, we are given that average is 4x and median is 8 greater than the smallest term. Now, smallest term is greater than 2. Therefore, median is less than 4x (since x>2). Therefore, median < mean. Sufficient. Choice C is the answer.
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Bunuel
Please provide your solution to this problem.

Thanks much for support
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Quote:
Set S contains five distinct positive integers, each of which is greater than 2. Is the mean of S greater than the median of S?


(1) The sum of the elements of S is equal to 20 times the smallest element of S.

(2) The median of S is 8 greater than the smallest element of S.

Statement 1 - Insufficient
Statement 2 - Insufficient

Combining both
Mean = 4a
Median = a +8
given a>2
Take a as {3,4,5,6,...}

Mean = {12, 16, 20, 24...}
Median = {11, 12, 13, 14...}
We get the answer Mean > Median so the answer is C
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