When rounded to the nearest hundredths digit, the number p becomes 6.7

Question

When rounded to the nearest hundredths digit, the number p becomes 6.72. What is the hundredths digit of p?

(1) The thousandths digit of p is 3. 
(2) The sum of the hundredths and the thousandths digits of p is 5

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TestPrepUnlimited · Answer

Let x be the thousandths digit of p, then p = 6.72x or p = 6.71x. The value of x will determine which one is p.

Statement 1:

If we had p = 6.713... it would not round up to 6.72, so we must have 6.723..., the hundredths digits must be 2. Sufficient.

Statement 2:

We know the hundredths digit must be either 1 or 2. Then this is telling us the thousandths digit is either 4 or 3. The thousandths digit will always be rounded down, so we can confirm the hundredths digit must be a 2 since we round down to 2. p = 6.72... Sufficient.

Ans: D

GMATinsight · Answer

abc.def

d = Tenth Digit
e = Hundredth Digit
f = Thousandth digit

p rounded to hundredths becoems 6.72

i.e. p may be number such as 6.7201 or it may be 6.715 to 6.719

Question : What is the hundredths digit of p?

Statememt 1 : The thousandths digit of p is 3.

i.e Hundredth digit has to be 2 of 6.72 because when thousandth digit is less than 5 then rounding off doesn't require hundredth digit to round up

SUFFICIENT

Statement 2 : The sum of the hundredths and the thousandths digits of p is 5

but minimum hundredth digit of rounded off 6.72 = 1
i.e. maximum thousandth digit = 5-1 = 4

because when thousandth digit is less than 5 then rounding off doesn't require hundredth digit to round up

SUFFICIENT

Answer: Option D

RS81 · Answer

Question analysis. 
p = 6.72 when rounded off to 2 digits.(hundredth is 2)
so p = 6.72A
if A={0,1,2,3,4} then hundredth digit is 2 else its 1.

Statement 1: 
A = 3 which is sufficient

Statement 2: 
A + hundredth digit = 5
hundredth digit min value = 1.
so A(max) = 4. 
This is sufficient

Hence answer is D

chetan2u · Answer

When rounded to the nearest hundredths digit, the number p becomes 6.72. What is the hundredths digit of p .
=> Means  6.715\leq{p}<6.725 . Thus   p can be 1 or 2.

(1) The thousandths digit of p is 3. 
 So two possibilities.. 
 6.713 , but when rounded off to nearest hundredths 6.713=6.71....NOT possible,  p
eq{1} 
 6.723 , and when rounded off to nearest hundredths 6.723=6.72....Yes, possible
SO p=2.
Sufficient

(2) The sum of the hundredths and the thousandths digits of p is 5 
We know p can be 1 or 2.
If p=1, then only possibility is 6.714, as 1+4=5, but when rounded off to nearest hundredths 6.714=6.71....NOT possible,  p
eq{1} 
If p=2, then only possibility is 6.723, as 2+3=5 and when rounded off to nearest hundredths 6.723=6.72....Yes
p=2
Suff

D

When rounded to the nearest hundredths digit, the number p becomes 6.7

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GMAT Data Sufficiency (DS) Questions

When rounded to the nearest hundredths digit, the number p becomes 6.7

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