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If x is an integer, what is the value of x?

(1) (2x + 1)(x – 2) < 0
(2) x^2 < 2

statement 1: (2x + 1)(x – 2) < 0
case A:
2x + 1 < 0; x < -1/2: [-1,-2,-3,...]
x - 2 > 0; x > 2; [3,4,5...]
no value of x is possible

case B:
2x + 1 > 0; x > -1/2: [0,1,2,...]
x -2 < 0: x < 2 [1,0,-1...]
x can be [0,1]

statement 2:
x^2 - 2 < 0
-1.4 < x < 1.4
x can be [-1,0,1]

combining both statements,
x can be [0,1].
Ans: E
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Nothing is given in qtn stem, lets jump to statements:

Statement (1):: (2x + 1)(x – 2) < 0 ==> -1/2 < x < 2 ==> x = 0 ,1; Not unique value, NOT SUfficient
Statement (2):: x^2 < 2 ==> (x^2 - 2) < 0 ==> -sqrt(2) < x < sqrt(2) ==> x = -1, 0, 1 Not unique value, NOT SUfficient

Lets combine both statements: x = 0,1 Not unique value, NOT SUfficient

E
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(1) (2x + 1)(x – 2) < 0

-1/2<x<2 so x can be 0 or 1

Not sufficient

(2) x^2 < 2

x can be -1, 0 or 1

Not sufficient

(1)+(2)

x can still be 0 or 1

Not sufficient

Answer is (E)

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Quote:
If x is an integer, what is the value of x?

(1) (2x + 1)(x – 2) < 0
(2) x^2 < 2

(1) insufic
"<" means the range in-between
(2x + 1)(x – 2) < 0
2x+1>0, x>-0.5
x-2<0, x<2
-0.5<x<2
x={0,1}

(2) insufic
x^2<2, |x|<√2~1.41
-1.41<x<1.41
x={-1,0,1}

(1/2) insufic
x={0,1}

Ans (E)
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Q. If x is an integer, what is the value of x?

(1) (2x + 1)(x – 2) < 0
-0.5 < x < 2 --> x= 0 or 1. We don't know which one.
NOT SUFFICIENT

(2) x^2 < 2
-1.4 < x < 1.4 --> x= -1, 0, or 1. We don't know which one.
NOT SUFFICIENT

(1)+(2)
Even we combine both statements, we can only deduce that x= 0 or 1. We don't know which one.
NOT SUFFICIENT

FINAL ANSWER IS (E)

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IMO E

If x is an integer, what is the value of x?

(1) (2x + 1)(x – 2) < 0
-∞ ........+Ve........... (-1/2) ...... -Ve ........ (2)............. +Ve
so, -1/2 < x < 2
x= { 0, 1 }
Not sufficient

(2) x^2 < 2
-√2 < x < √2
x= { 0, 1 }
Not sufficient

Together, x= { 0, 1 }
Not sufficient
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Ans Should be E.

If x is an integer, what is the value of x?

St (1):
(2x + 1)(x – 2) < 0

Either [ (2x + 1) > 0 and (x – 2) <0 ] or [ (2x + 1) < 0 and (x – 2) >0 ]

so -0.5 < x < 2 i.e X could be 0 or 1 . Since we don't have an conclusive ans . Its st 1 is insuffi.

St (2):
x^2 < 2

-1.41 < x < 1.41 .

again x can be 0 or 1 . Again we don't have an conclusive ans . Its st 2 is insuffi.

By Combining st 1 and 2 also it's insuffi.. ,since x can be 0 or 1 .
So ans is E , IMO .
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If x is an integer, what is the value of x?

(1) (2x + 1)(x – 2) < 0
(2) x^2 < 2

1) when 2x + 1 < 0, x < -1/2 (x can be -1, -2...as its an integer), but in that case (x -2) will also be negative, so x has to be either 0 or positive. Again, when x -2 < 0 or, x < 2, both 0 and 1 will satisfy the condition. not sufficient
2) x^2 < 2, |x| < 1.41. not sufficient
Together, x can be either 0 or 1. Not sufficient
E is the answer
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I choose E.

Statement 1:
Intersection for (2x+1) to be positive and (x-2) to be negative is -1< x < 2. Giving possible integers 0,1

Not Suff.

Statement 2

X can take -1,0,1
Not suff.

Combining the two still leaves us with 1,0
Not suff.

Hence, E.

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Ans: E
x=int
1)(2x + 1)(x – 2) < 0
-1/2<x<2..so X can be 0 and 1..not sufficient
2)x^2 < 2
-root2<x<root2..so x can be -1,0,1..not sufficient
combine..both 0 and 1 are possible..not sufficient
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Bunuel

Competition Mode Question




If x is an integer, what is the value of x?

(1) (2x + 1)(x – 2) < 0
(2) x^2 < 2

If x is an integer, what is the value of x?

(1) (2x + 1)(x – 2) < 0:

The "roots" are -1/2 and 2. "<" sign indicates that the solution lies between the roots, thus -1/2 < x < 2. This implies that x can be 0 or 1. Sufficient.
Check Solving Quadratic Inequalities - Graphic Approach for more on this: https://gmatclub.com/forum/solving-quad ... 70528.html

(2) x^2 < 2 --> \(-\sqrt{2}<x<\sqrt{2}\) --> x can be -1, 0, or 1. Not sufficient.

(1)+(2) x can still take more than 1 value: 0 or 1. Not sufficient.

Answer: E.
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