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Difficulty:
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Question Stats:
90% (00:40) correct
10%
(00:44)
wrong
based on 78
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If r, s and t are numbers, is r = 60 ?
(1) The average (arithmetic mean) of r, s and t is 20.
(2) s = t = 0
(1) The average (arithmetic mean) of r, s and t is 20.
(2) s = t = 0
Posts: 266
IMO C
Qtn asks is r=60?
Statement 1: arithmetic mean(r, s, t) = 20 i.e. (r+s+t)/3 = 20 or (r+s+t)= 60 Since we do not know s & t, NOT Sufficient
Statement 2: s = t = 0 SO??? NOT Sufficient
Lets combine:
(r+s+t)= 60 & s = t = 0
==> r = 60
SUFFICIENT
Qtn asks is r=60?
Statement 1: arithmetic mean(r, s, t) = 20 i.e. (r+s+t)/3 = 20 or (r+s+t)= 60 Since we do not know s & t, NOT Sufficient
Statement 2: s = t = 0 SO??? NOT Sufficient
Lets combine:
(r+s+t)= 60 & s = t = 0
==> r = 60
SUFFICIENT
yashikaaggarwal
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Schools: Cranfield (A) Warwick MiM "23 (M)
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Schools: Cranfield (A) Warwick MiM "23 (M)
Posts: 3,095
Answer is C
Statement 1: The average (arithmetic mean) of r, s and t is 20.
=> (R+S+T)/3=20 => R+S+T = 60
(But we don't know the value of S and T to determine R)
(Not sufficient)
Statement 2: S=T=0
(But what about R? We need value of R to prove whether it's equivalent to 60 or not)
(Not Sufficient)
Statement 1&2:
=> R+S+T = 60 => S=T=0
=> R+0+0=60. => R=60
{Sufficient}
Posted from my mobile device
_________________
Statement 1: The average (arithmetic mean) of r, s and t is 20.
=> (R+S+T)/3=20 => R+S+T = 60
(But we don't know the value of S and T to determine R)
(Not sufficient)
Statement 2: S=T=0
(But what about R? We need value of R to prove whether it's equivalent to 60 or not)
(Not Sufficient)
Statement 1&2:
=> R+S+T = 60 => S=T=0
=> R+0+0=60. => R=60
{Sufficient}
Posted from my mobile device
_________________
SajjadAhmad
Question: Is r = 60?
Statement 1: r+s+t = 60
If s = t = 0 then r = 60
If s and t are positive then r ≠ 60 hence
NOT SUFFICIENT
Statement 2: s = t = 0
No informaiton about r hence
NOT SUFFICIENT
COmbining the statements
r+s+t = 60 and s = t = 0 then r = 60
SUFFICIENT
Answer: Option C
_________________
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