Last visit was: 26 Apr 2026, 00:30 It is currently 26 Apr 2026, 00:30
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,831
Own Kudos:
811,317
 [3]
Given Kudos: 105,889
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,831
Kudos: 811,317
 [3]
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
User avatar
Nevernevergiveup
User avatar
Retired Moderator
Joined: 18 Sep 2014
Last visit: 20 Aug 2023
Posts: 998
Own Kudos:
Given Kudos: 79
Location: India
Products:
Posts: 998
Kudos: 3,080
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
Deepakjhamb
Joined: 29 Mar 2020
Last visit: 15 Sep 2022
Posts: 215
Own Kudos:
137
 [3]
Given Kudos: 14
Location: India
Concentration: General Management, Leadership
GPA: 3.96
WE:Business Development (Telecommunications)
Posts: 215
Kudos: 137
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
avatar
Deepakjhamb
Joined: 29 Mar 2020
Last visit: 15 Sep 2022
Posts: 215
Own Kudos:
Given Kudos: 14
Location: India
Concentration: General Management, Leadership
GPA: 3.96
WE:Business Development (Telecommunications)
Posts: 215
Kudos: 137
Kudos
Add Kudos
Bookmarks
Bookmark this Post
[quote="Nevernevergiveup"]32 is not but 2^5 so have 3 zeros(tens) and a 6 to get divided by 4 2s so just need A where we have one more 2 in 253

Posted from my mobile device[/quote

Seems ur analysis is wrong

See for dovisibility by 2 last number should be divisible by 2 , for divisibility by 4 last 2 digits and thus by 32 last 5 digits

So until u know DE u cannot be sure
User avatar
akadiyan
User avatar
Retired Moderator
Joined: 31 May 2017
Last visit: 20 Jun 2025
Posts: 724
Own Kudos:
706
 [1]
Given Kudos: 53
Concentration: Technology, Strategy
Products:
Posts: 724
Kudos: 706
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

Note:
Divisibility rule for 32 - If the last 5 digits of a number should be divisible by 32, then the whole number is divisible by 32.

(1) Three-digit integer ABC = 253
We do not know any information about DE.
Option 1 - Insufficient.

(2) Two-digit integer DE = 13
This option gives us DE from which we can calculate the last 5 digits of the number and then we can find whether the number is divisible by 32 .

Option 2 - Sufficient.

Ans B
avatar
GCMEMBER
Joined: 09 Dec 2019
Last visit: 03 Jun 2021
Posts: 123
Own Kudos:
176
 [1]
Given Kudos: 5
Posts: 123
Kudos: 176
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

For an integer to be divisible by 32, last 5 digits should be divisible by 5.

(1) Three-digit integer ABC = 253
Last 5 digits not known.
Not sufficient

(2) Two-digit integer DE = 13
Last 5 digits known
Sufficient

Option B

Posted from my mobile device
User avatar
CEdward
Joined: 11 Aug 2020
Last visit: 14 Apr 2022
Posts: 1,161
Own Kudos:
Given Kudos: 332
Posts: 1,161
Kudos: 289
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The answer is B.
Statement 1 : Insufficient b/c this is a ridiculous proposition to ask one to divide a 10 digit number by 32. What is easy to hone in on is DE (which we can see by the presence of 3 0s). DE can be a multiple of 32 or not. So the integer may or may not be divisible by 32.
e.g. DE = 32 then yes
e.g. DE = 33 then no
Statement 2: Following from the logic of the previous statement we see that DE = 13.
13/32 is not an integer.
Sufficient.
User avatar
Nevernevergiveup
User avatar
Retired Moderator
Joined: 18 Sep 2014
Last visit: 20 Aug 2023
Posts: 998
Own Kudos:
Given Kudos: 79
Location: India
Products:
Posts: 998
Kudos: 3,080
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Deepakjhamb
Nevernevergiveup
32 is not but 2^5 so have 3 zeros(tens) and a 6 to get divided by 4 2s so just need A where we have one more 2 in 253

Posted from my mobile device[/quote

Seems ur analysis is wrong

See for dovisibility by 2 last number should be divisible by 2 , for divisibility by 4 last 2 digits and thus by 32 last 5 digits

So until u know DE u cannot be sure

yup you are right. thanks
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 25 Apr 2026
Posts: 11,229
Own Kudos:
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,229
Kudos: 45,021
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

(1) Three-digit integer ABC = 253
(2) Two-digit integer DE = 13


Project DS Butler Data Sufficiency (DS3)


For DS butler Questions Click Here


Divisibility by 2 and it’s power depend on the number of digits equal to the power.
2^1 : look for divisibility of one digit by 2
2^2 : look for divisibility of two digits ( ones and tens) by 4.
So 32 or 2^5 will depend on last 5 digits from right.
A,BC6,7DE,000.
Last 3 0s tell us that it is divisible by 2^3, but for 2^5, we have to look for divisibility of DE,000 by 32.

Statement II gives us the value of DE, so we can find divisibility of 13000 by 32 and whatever be the answer will be the answer for divisibility of the entire term by 32.

B
User avatar
unraveled
Joined: 07 Mar 2019
Last visit: 10 Apr 2025
Posts: 2,706
Own Kudos:
Given Kudos: 763
Location: India
WE:Sales (Energy)
Posts: 2,706
Kudos: 2,329
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

\(32 = 2^5\)
\(A,BC6,7DE,000 = A,BC6,7DE * 1,000 = A,BC6,7DE * (10)^3 = A,BC6,7DE * 2^3 * 5^3\)
Thus,
A,BC6,7DE,000 is divisible by \(2^3\)

Hence, we need to check whether A,BC6,7DE is divisible by \(2^2 = 4\)
\(\implies\) we need to check only the last two digit(DE) of A,BC6,7DE for divisibility by 4.

(1) Three-digit integer ABC = 253
DE may or may not be divisible by 4

INSUFFICIENT.

(2) Two-digit integer DE = 13
13 is not divisible by 4.

SUFFICIENT.

Answer B.
User avatar
exc4libur
Joined: 24 Nov 2016
Last visit: 22 Mar 2022
Posts: 1,680
Own Kudos:
Given Kudos: 607
Location: United States
Posts: 1,680
Kudos: 1,469
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Consider a ten-digit integer A,BC6,7DE,000. Is the integer divisible by 32?

(1) Three-digit integer ABC = 253
(2) Two-digit integer DE = 13

32=2^5
abc67de*1000 is div if we have 5 two's (2)
1000=10^3 has 2^3
find if abc67de is div by 2^2

(1) insuf

(2) sufic

abc6713 is not even

(B)
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,987
Own Kudos:
Posts: 38,987
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109831 posts
498 posts
212 posts