Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
10 Mar 2025, 00:30
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
85% (01:20) correct
15%
(02:06)
wrong
based on 61
sessions
History
Date
Time
Result
Not Attempted Yet
A plane averages 60 miles per hour slower than a second plane. If the slower plane completes a particular trip in three hours, how long will the faster plane take to complete the same trip?
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
(1) The trip was 1,590 miles.
(2) The slower plane travels at 530 miles per hour.
10 Mar 2025, 02:08
Kudos
Bookmarks
Bunuel
First plane speed = S | Time = 3 hours
Second plane speed = S+60 | T = ?
Distance is constant so
S*3 = (S+60)*T
i.e. to calculate T we need the value of S
Question: S = ?
Statement 1: D = 1590
i.e. 1590 = S*3
i.e. S = 530
SUFFICIENT
Statement 2: S = 530
SUFFICIENT
Answer: Option D
Related Video:
Please Like and Subscribe to YouTube channel if you like the video and access 1100+ more FREE videos. Every subscription matters!!!
If you like to subscribe to modular courses on Quant and DI then please visit the following link: https://gmatinsight.com/gmat-2/
10 Mar 2025, 03:10
Kudos
Bookmarks
Step 1: Define variables
Let S be the speed of the slower plane.
Let F be the speed of the faster plane.
Given that the slower plane is 60 mph slower than the faster plane:
F = S + 60
Step 2: Use the given information
The slower plane takes 3 hours for the trip, so the total distance (D) is:
D = S × 3
Step 3: Analyze the statements
(1) The trip was 1,590 miles.
- Using D = 1,590, we get:
S × 3 = 1,590
S = 1,590 / 3 = 530 mph
- This allows us to determine S, so we can also find F:
F = 530 + 60 = 590 mph
- Now, time for the faster plane:
Time = Distance / Speed = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
(2) The slower plane travels at 530 miles per hour.
- This directly gives S = 530 mph, so we can compute F:
F = 530 + 60 = 590 mph
- Since distance is S × 3 = 1,590, we already know the distance.
Time for the faster plane:
Time = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
Step 4: Conclusion
Each statement alone is sufficient to answer the question.
Answer: D (Each statement alone is sufficient)
Let S be the speed of the slower plane.
Let F be the speed of the faster plane.
Given that the slower plane is 60 mph slower than the faster plane:
F = S + 60
Step 2: Use the given information
The slower plane takes 3 hours for the trip, so the total distance (D) is:
D = S × 3
Step 3: Analyze the statements
(1) The trip was 1,590 miles.
- Using D = 1,590, we get:
S × 3 = 1,590
S = 1,590 / 3 = 530 mph
- This allows us to determine S, so we can also find F:
F = 530 + 60 = 590 mph
- Now, time for the faster plane:
Time = Distance / Speed = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
(2) The slower plane travels at 530 miles per hour.
- This directly gives S = 530 mph, so we can compute F:
F = 530 + 60 = 590 mph
- Since distance is S × 3 = 1,590, we already know the distance.
Time for the faster plane:
Time = 1,590 / 590 = 2.7 hours
- This statement alone is sufficient.
Step 4: Conclusion
Each statement alone is sufficient to answer the question.
Answer: D (Each statement alone is sufficient)
