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Let the three share prices be H (highest), M (middle), and L (lowest).

Question: Is H+M+L < 9,800?

Statement (1): Highest price (H) is 3,300
  • H+M+L<=9900
  • So, H + M + L can be less than or greater than 9800
  • Insufficient.
Statement (2): Middle price (M) is 110 more than Lowest price (L)
  • M = L + 110.
  • Without knowing H or the actual values of M and L, we cannot determine the sum.
  • Insufficient.
Combined (1) and (2):
  • From (1), H = 3,300.
  • From (2), M = L + 110.
  • Since H is the highest price, the middle price (M) cannot exceed 3,300.
  • To test the maximum possible sum: Let M be as large as possible (3,300).
  • If M = 3,300, then L = 3,300 - 110 = 3,190.
  • Max Sum = 3,300 (H) + 3,300 (M) + 3,190 (L) = 9,790.
  • Since the maximum possible sum is 9,790, the total will always be less than 9,800.
  • Sufficient.
Correct Answer: C

Sketchitesh
Rakesh Bought 3 Shares of Power Infra. One on 31st April'24, one on 23rd May'24 and one on 1st of June'25. Is the sum of buy price of shares is less than 9800$?

(1) Highest buy price ever out of 3 buy prices is 3300$
(2) Second highest buy price is 110$ more than Lowest Buy Price.



To determine B1+B2+B3<9800

B3= 3300. If B1=B2=B3 then B1+B2+B3= 9900 or B1= 1, B2 =1 and B3= 3300 then 3302
(so Not sufficient)
B1=1, B2= 1102, B3= 1102 then Ok but B1 =8800 and B2= 9900 so not sufficient.

Both combine

B3= 3300, highest case scenario, B2= 3300 then B1= 3190 then Sum= 9790. Sufficient.
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