Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2212:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
24 Dec 2025, 09:00
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
57% (02:07) correct
43%
(01:39)
wrong
based on 165
sessions
History
Date
Time
Result
Not Attempted Yet
A museum recorded the number of visitors for each of 12 consecutive days. If the visitor counts were all different and the smallest daily visitor count was 27, what was the largest daily visitor count?
(1) The range of the visitor counts for the 12 days was at most 12.
(2) The median visitor count over the 12 days was 33.
I31-13
(1) The range of the visitor counts for the 12 days was at most 12.
(2) The median visitor count over the 12 days was 33.
I31-13
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
24 Dec 2025, 10:00
Kudos
Bookmarks
GMAT Club Official Explanation:
A museum recorded the number of visitors for each of 12 consecutive days. If the visitor counts were all different and the smallest daily visitor count was 27, what was the largest daily visitor count?
(1) The range of the visitor counts for the 12 days was at most 12.
The range equals the largest count minus the smallest count. Since the smallest daily count was 27 and the range was at most 12, the largest count could be at most 39. Because the 12 daily counts were all different, they must be 12 of the 13 consecutive integers from 27 to 39.
If 39 is missing, the counts could be {27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38}, so the largest is 38.
If a different number is missing, the counts could include 39, such as {27, 28, 29, 30, 31, 32, 34, 35, 36, 37, 38, 39}, so the largest is 39.
Not sufficient.
(2) The median visitor count over the 12 days was 33.
For 12 numbers, the median is the average of the 6th and 7th numbers when the counts are ordered from least to greatest. A median of 33 means the 6th and 7th counts sum to 66. This, however does not determine the largest count, different sets with smallest 27 and median 33 can have different largest values. Not sufficient.
(1)+(2) From (1), largest is either 38 or 39. If largest = 38, the only set of 12 distinct integers from 27 to 38 is {27, 28, ..., 38}. Its median is (32+33)/2 = 32.5, not 33. So largest cannot be 38. Therefore, largest must be 39. (With largest = 39, we must choose 12 numbers from 27 to 39. To have median 33, the 6th and 7th numbers must average to 33. The only set that works is {27, 28, 29, 30, 31, 32, 34, 35, 36, 37, 38, 39} (omitting 33). This gives largest = 39). Sufficient.
Answer: C.
General Discussion
24 Dec 2025, 09:37
Kudos
Bookmarks
S1
range <=12
L-27<=12
L<=39
If all are distinct integers
27+11 = 38
38<=L<=39
We don't know if it's 38 or 39
Insufficient
S2
Median = avg of 6th and 7th term = 33
L can be anything as median is not impacted by the extreme values, till the time values are sorted
insufficient
Combined
median = 33
smallest possible value for 7th term is 34
smallest value for L = 34=5 = 39
Sufficient
Answer C
range <=12
L-27<=12
L<=39
If all are distinct integers
27+11 = 38
38<=L<=39
We don't know if it's 38 or 39
Insufficient
S2
Median = avg of 6th and 7th term = 33
L can be anything as median is not impacted by the extreme values, till the time values are sorted
insufficient
Combined
median = 33
smallest possible value for 7th term is 34
smallest value for L = 34=5 = 39
Sufficient
Answer C
Bunuel
